5、编写程序实现两个整数集合的基本运算：S1+S2 集合并运算 S1-S2 集合差运算 S1*S2 集合交运算 要求：输入整数集合{2 4 1 3 5}和{2 5 10}，输出前者元素个数以及它们进行集合并、差、交运算后的结果。用C++写出代码

以下是用C++实现的代码：

#include<iostream>
#include<set>
using namespace std;

int main()
{
    set<int> s1 = {2, 4, 1, 3, 5}; // 定义集合S1
    set<int> s2 = {2, 5, 10}; // 定义集合S2

    // 集合并运算
    set<int> s_union;
    set_union(s1.begin(), s1.end(), s2.begin(), s2.end(), inserter(s_union, s_union.begin()));

    // 集合差运算
    set<int> s_diff;
    set_difference(s1.begin(), s1.end(), s2.begin(), s2.end(), inserter(s_diff, s_diff.begin()));

    // 集合交运算
    set<int> s_intersection;
    set_intersection(s1.begin(), s1.end(), s2.begin(), s2.end(), inserter(s_intersection, s_intersection.begin()));

    // 输出结果
    cout << "S1的元素个数为：" << s1.size() << endl;
    cout << "S2的元素个数为：" << s2.size() << endl;
    cout << "S1和S2的集合并为：";
    for(auto it = s_union.begin(); it != s_union.end(); it++)
        cout << *it << " ";
    cout << endl;
    cout << "S1和S2的集合差为：";
    for(auto it = s_diff.begin(); it != s_diff.end(); it++)
        cout << *it << " ";
    cout << endl;
    cout << "S1和S2的集合交为：";
    for(auto it = s_intersection.begin(); it != s_intersection.end(); it++)
        cout << *it << " ";
    cout << endl;

    return 0;
}

输出结果为：

S1的元素个数为：5
S2的元素个数为：3
S1和S2的集合并为：1 2 3 4 5 10
S1和S2的集合差为：1 3 4
S1和S2的集合交为：2 5