python石头剪刀布三局两胜对话框
时间: 2024-04-20 08:21:43 浏览: 178
Python石头剪刀布游戏是一种简单的游戏,通常是两个人进行对战。下面是一个示例代码,实现了一个基于对话框的三局两胜的石头剪刀布游戏:
```python
import random
import tkinter as tk
from tkinter import messagebox
# 定义游戏规则
rules = {
"rock": "scissors",
"scissors": "paper",
"paper": "rock"
}
# 初始化计分
player_score = 0
computer_score = 0
# 定义游戏逻辑
def play(player_choice):
global player_score, computer_score
# 计算电脑的选择
computer_choice = random.choice(list(rules.keys()))
# 判断胜负
if player_choice == computer_choice:
result = "平局"
elif rules[player_choice] == computer_choice:
result = "你赢了!"
player_score += 1
else:
result = "电脑赢了!"
computer_score += 1
# 显示结果对话框
messagebox.showinfo("结果", f"你选择了:{player_choice}\n电脑选择了:{computer_choice}\n\n{result}")
# 判断是否达到两局胜利条件
if player_score == 2 or computer_score == 2:
if player_score > computer_score:
winner = "你"
else:
winner = "电脑"
messagebox.showinfo("游戏结束", f"{winner}获得了最终胜利!")
# 重置计分
player_score = 0
computer_score = 0
# 创建游戏界面
window = tk.Tk()
window.title("石头剪刀布游戏")
# 创建按钮
rock_button = tk.Button(window, text="石头", command=lambda: play("rock"))
rock_button.pack()
scissors_button = tk.Button(window, text="剪刀", command=lambda: play("scissors"))
scissors_button.pack()
paper_button = tk.Button(window, text="布", command=lambda: play("paper"))
paper_button.pack()
# 运行游戏
window.mainloop()
```
这段代码使用了`tkinter`库来创建游戏界面和对话框,通过点击按钮来选择石头、剪刀或布,并与电脑进行对战。每局结束后会弹出对话框显示结果,当某一方达到两局胜利时,会弹出游戏结束的对话框。
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