python 石头剪刀布代码

下面是Python实现的石头剪刀布游戏代码：

import random

gestures = ['石头', '剪刀', '布']

player_gesture = input("请输入你的选择（石头、剪刀或布）：")
computer_gesture = random.choice(gestures)

if player_gesture == computer_gesture:
    result = "平局"
elif (player_gesture == '石头' and computer_gesture == '剪刀') or \
     (player_gesture == '剪刀' and computer_gesture == '布') or \
     (player_gesture == '布' and computer_gesture == '石头'):
    result = "你赢了"
else:
    result = "计算机赢了"

print(f"你的选择是：{player_gesture}")
print(f"计算机的选择是：{computer_gesture}")
print(f"结果：{result}")

相关问题

python石头剪刀布代码

好的，以下是Python实现石头剪刀布游戏的代码：

import random

def play():
    user = input("请出拳（石头、剪刀、布）：")
    computer = random.choice(['石头', '剪刀', '布'])
    print(f"你出拳为：{user}，电脑出拳为：{computer}")
    
    if user == computer:
        return "平局"
    elif is_win(user, computer):
        return "你赢了！"
    else:
        return "电脑赢了！"

def is_win(player, opponent):
    if (player == '石头' and opponent == '剪刀') or \
       (player == '剪刀' and opponent == '布') or \
       (player == '布' and opponent == '石头'):
        return True
    return False

print(play())

在运行代码时，程序会随机生成电脑出拳的结果，然后与用户输入的结果进行比较，从而决定胜负。

python石头剪刀布游戏代码

游戏介绍：
数字1代表石头
数字2代表剪刀
数字3代表布

游戏次数：

import random

def game():
    count = 0
    while count < 5:
        count += 1
        guess = int(input("请输入你的选择（1-石头，2-剪刀，3-布）："))
        computer = random.randint(1, 3)

        if guess == computer:
            print("平局！")
        elif (guess == 1 and computer == 2) or (guess == 2 and computer == 3) or (guess == 3 and computer == 1):
            print("你赢了！")
        else:
            print("你输了！")

game()