A集合： [{begintime:2020-01-01 00:04:00,endtime:2020-01-01 00:06:00}, {begintime:2020-01-01 00:01:05,endtime:2020-01-01 00:03:15}, {begintime:2020-01-01 00:09:00,endtime:2020-01-01 00:10:00}, {begintime:2020-01-01 00:07:35,endtime:2020-01-01 00:08:40}, {begintime:2020-01-01 00:12:00,endtime:2020-01-01 00:17:00}, {begintime:2020-01-01 00:12:05,endtime:2020-01-01 00:13:10}, {begintime:2020-01-01 00:19:00,endtime:2020-01-01 00:21:00}, {begintime:2020-01-01 00:15:20,endtime:2020-01-01 00:20:45}]  期望得到的输出结果： [{begintime:2020-01-01 00:01:05,endtime:2020-01-01 00:03:15}, {begintime:2020-01-01 00:04:00,endtime:2020-01-01 00:06:00}, {begintime:2020-01-01 00:07:35,endtime:2020-01-01 00:08:40}, {begintime:2020-01-01 00:09:00,endtime:2020-01-01 00:10:00}, {begintime:2020-01-01 00:12:00,endtime:2020-01-01 00:21:00}]

好的，根据您的描述，您想要对给定的A集合进行排序，按照每个时间段的开始时间顺序，然后合并时间段，使得它们不重叠，对吗？

如果是的话，可以使用以下代码实现：

# 对时间段按照开始时间进行排序
A = sorted(A, key=lambda x: x['begintime'])

merged = []

# 对时间段进行合并
for interval in A:
    if not merged or merged[-1]['endtime'] < interval['begintime']:
        merged.append(interval)
    else:
        merged[-1]['endtime'] = max(merged[-1]['endtime'], interval['endtime'])

# 输出结果
print(merged)

输出结果应该是:

[{begintime:2020-01-01 00:01:05,endtime:2020-01-01 00:03:15}, {begintime:2020-01-01 00:04:00,endtime:2020-01-01 00:06:00}, {begintime:2020-01-01 00:07:35,endtime:2020-01-01 00:08:40}, {begintime:2020-01-01 00:09:00,endtime:2020-01-01 00:10:00}, {begintime:2020-01-01 00:12:00,endtime:2020-01-01 00:21:00}]

希望这能回答您的问题。