C# 写一个用代码编译一个文件夹里所有的sln文件
时间: 2024-02-16 11:03:33 浏览: 24
可以使用以下代码实现:
```csharp
using System;
using System.IO;
using System.Linq;
using Microsoft.Build.Evaluation;
using Microsoft.Build.Execution;
namespace CompileAllSlns
{
class Program
{
static void Main(string[] args)
{
var folderPath = @"C:\SlnFolder\"; // 文件夹路径
var slns = Directory.GetFiles(folderPath, "*.sln", SearchOption.AllDirectories); // 获取所有的sln文件
foreach (var sln in slns)
{
var pc = new ProjectCollection();
var project = pc.LoadProject(sln);
var buildParameters = new BuildParameters
{
Loggers = new[] { new ConsoleLogger() }
};
var buildRequestData = new BuildRequestData(project.CreateProjectInstance(), new[] { "Build" });
var buildResult = BuildManager.DefaultBuildManager.Build(buildParameters, buildRequestData);
if (buildResult.OverallResult == BuildResultCode.Success)
{
Console.WriteLine($"Compiled {sln} successfully.");
}
else
{
Console.WriteLine($"Failed to compile {sln}.");
}
}
Console.WriteLine("Compilation completed.");
Console.ReadLine();
}
}
}
```
注意,需要在项目中引用 `Microsoft.Build` 包。此代码将编译指定文件夹中的所有 .sln 文件。每个解决方案都将使用默认的 MSBuild 目标 "Build" 进行编译,并输出编译结果。