写一个银行家算法代码
时间: 2023-03-05 08:27:18 浏览: 60
我可以提供一些参考,但是最终的银行家算法代码可能会根据你的具体要求而有所不同。以下是一个基本的银行家算法代码:int number_of_processes = // 进程数
int number_of_resources = // 资源数int[][] max = new int[number_of_processes][number_of_resources]; // 最大需求矩阵
int[][] allocation = new int[number_of_processes][number_of_resources]; // 分配矩阵
int[][] need = new int[number_of_processes][number_of_resources]; // 剩余需求矩阵
int[] available = new int[number_of_resources]; // 可用资源数// 初始化 max, allocation, need, availableboolean is_safe(){
int[] work = available;
boolean[] finish = new boolean[number_of_processes];
for(int i = 0; i < number_of_processes; ++i){
finish[i] = false;
}
int num_finish = 0;
while (num_finish < number_of_processes){
boolean found_process = false;
for(int i = 0; i < number_of_processes; ++i){
if(!finish[i] && can_finish(i, work)){
found_process = true;
finish[i] = true;
num_finish++;
for(int j = 0; j < number_of_resources; ++j){
work[j] += allocation[i][j];
}
}
}
if(!found_process){
return false;
}
}
return true;
}boolean can_finish(int i, int[] work){
for(int j = 0; j < number_of_resources; ++j){
if(need[i][j] > work[j]){
return false;
}
}
return true;
}
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