mapstruct报错 Consider to declare/implement a mapping method: "PostInvestOutVO map(PostInvestmentReportDO value)".
时间: 2024-03-09 17:44:10 浏览: 22
如果您使用了MapStruct来实现对象的映射,那么您需要在`@Mapper`注解中添加`componentModel`属性,指定生成的映射器类使用的依赖注入方式。如果您想使用Spring依赖注入,可以将`componentModel`属性设置为`"spring"`。
例如:
```java
@Mapper(componentModel = "spring")
public interface PostInvestmentMapper {
PostInvestOutVO map(PostInvestmentReportDO value);
}
```
另外,MapStruct生成的映射器类需要被Spring容器扫描到。您可以在Spring的配置类中添加`@MapperScan`注解来扫描指定的映射器包。例如:
```java
@Configuration
@MapperScan("com.example.mapper")
public class AppConfig {
// ...
}
```
在上面的示例中,`@MapperScan`注解指定了`com.example.mapper`包,表示该包下的所有MapStruct映射器类都会被自动注册到Spring容器中。
相关问题
Consider to declare/implement a mapping method: "PostInvestOutVO map(PostInvestmentReportDO value)".
Certainly, I can help you with that. Based on the method signature you have provided, it seems like you want to create a mapping method that takes an instance of the class `PostInvestmentReportDO` as input and returns an instance of the class `PostInvestOutVO`. Here's an example implementation of the method:
```java
public PostInvestOutVO map(PostInvestmentReportDO value) {
PostInvestOutVO result = new PostInvestOutVO();
result.setInvestmentId(value.getInvestmentId());
result.setInvestmentName(value.getInvestmentName());
result.setInvestmentType(value.getInvestmentType());
result.setInvestmentAmount(value.getInvestmentAmount());
result.setInvestmentDate(value.getInvestmentDate());
result.setInvestmentStatus(value.getInvestmentStatus());
return result;
}
```
In the above implementation, I have created an instance of `PostInvestOutVO` and set its properties based on the corresponding properties of the input `PostInvestmentReportDO` object. You can modify this implementation as per your specific requirements.
还是报错:cannot declare '::main' to be a template
这个错误通常是因为你的代码中使用了 C++ 的模板语法,但是忘记了给 main 函数添加正确的参数列表。在 C++ 标准中,main 函数必须具有以下两种形式之一:
1. `int main()`
2. `int main(int argc, char* argv[])`
如果你想在 main 函数中使用模板,可以像这样定义:
```
template<typename T>
int main(int argc, char* argv[]) {
// your code here
return 0;
}
```
但是请记住,这不是标准的 main 函数定义方式。如果你只是想编写一个普通的 C++ 程序,可以使用上面提到的两种形式之一。