我有一个dataframe，有两个columns，code和count，我需要by code去统计每个code对应的count栏位的数值加总，生成一个新dataframe

好的，你可以使用`groupby()`和`sum()`方法来实现这个需求。以下是示例代码：

import pandas as pd

# 假设你的原始数据存储在df变量中
# 创建一个新的DataFrame，按code分组并计算count列的总和
new_df = pd.DataFrame(df.groupby('code')['count'].sum())

# 输出新的DataFrame
print(new_df)

这段代码会按照`code`列进行分组，并计算每个组中`count`列的总和，最终生成一个新的DataFrame。你可以将代码中的`df`替换为你实际使用的DataFrame对象。

相关问题

'DataFrame' object has no attribute 'append' File "D:\chapter12\demo\code\123.py", line 24, in <module> hit_count_7 = hit_count_7.append([{'用户数': time}], ignore_index=True) AttributeError: 'DataFrame' object has no attribute 'append'

Based on the error message you provided, it seems that you are trying to use the `append()` method on a DataFrame object, but this method does not exist for DataFrames. Instead, you can use the `concat()` method to concatenate DataFrames vertically.

Here's an example of how you can use `concat()` to append a row to a DataFrame:

import pandas as pd

# create an empty DataFrame
df = pd.DataFrame(columns=['用户数'])

# append a row to the DataFrame
time = 10
new_row = pd.DataFrame({'用户数': [time]})
df = pd.concat([df, new_row], ignore_index=True)

# print the updated DataFrame
print(df)

This should create a new DataFrame with one row containing the value of `time` in the `用户数` column. You can modify this code to fit your specific use case.

class KnnRegressorCV: def __init__(self, ks=list(range(1, 21)), cv=LFold(5)): self.ks = ks self.cv = cv # YOUR CODE HERE def fit(self, x, y): df = pd.DataFrame(columns=["KValue", "LFoldID", "MSE_train", "MSE_test"]) count = 0 for k in self.ks: for index, each in enumerate(self.cv.split(x, y)): mse_train, mse_test = runknn(k, each[0], each[1], each[2].reshape(-1), each[3].reshape(-1)) df.at[count, "KValue"] = k df.at[count, "LFoldID"] = index df.at[count, "MSE_train"] = mse_train df.at[count, "MSE_test"] = mse_test count += 1 self.bestK = find_best_k(df, self.ks) self.y_train_ = y self.x_train_kdtree_ = KDTree(x) print("bestK internal:", self.bestK) return self # YOUR CODE HERE def predict(self, x): _, neighbours = self.x_train_kdtree_.query(x, k=self.bestK) neighbours = neighbours.reshape(len(x), self.k) neighbour_labels = self.y_train_[neighbours] pred = np.mean(neighbour_labels, axis=1) return pred给这段代码加注释

# 导入需要的库
import pandas as pd
from sklearn.neighbors import KDTree

# 定义 KNN 回归交叉验证类
class KnnRegressorCV:     
    def __init__(self, ks=list(range(1, 21)), cv=LFold(5)): # 初始化方法，参数包括 k 值列表和交叉验证方法
        self.ks = ks         # k 值列表
        self.cv = cv         # 交叉验证方法
         
    def fit(self, x, y):    # 模型训练方法，参数包括自变量和因变量
        # 定义空的数据框用于存储模型评估结果
        df = pd.DataFrame(columns=["KValue", "LFoldID", "MSE_train", "MSE_test"]) 
        count = 0  # 定义计数器
        for k in self.ks:  # 遍历 k 值列表
            for index, each in enumerate(self.cv.split(x, y)): # 遍历交叉验证的训练集和测试集
                # 调用 runknn 函数进行模型评估，返回训练集和测试集的 MSE
                mse_train, mse_test = runknn(k, each[0], each[1], each[2].reshape(-1), each[3].reshape(-1)) 
                # 将评估结果存入数据框
                df.at[count, "KValue"] = k 
                df.at[count, "LFoldID"] = index 
                df.at[count, "MSE_train"] = mse_train 
                df.at[count, "MSE_test"] = mse_test 
                count += 1     # 计数器加 1
        # 调用 find_best_k 函数找到 MSE 最小的 k 值
        self.bestK = find_best_k(df, self.ks) 
        self.y_train_ = y    # 存储因变量
        self.x_train_kdtree_ = KDTree(x)  # 存储自变量的 KDTree
        print("bestK internal:", self.bestK) # 打印最优的 k 值
        return self      # 返回模型自身
     
    def predict(self, x):   # 预测方法，参数为自变量
        _, neighbours = self.x_train_kdtree_.query(x, k=self.bestK) # 找到最近的 k 个邻居
        neighbours = neighbours.reshape(len(x), self.k)  # 将邻居的索引转为二维数组
        neighbour_labels = self.y_train_[neighbours]  # 找到邻居的因变量值
        pred = np.mean(neighbour_labels, axis=1)  # 对邻居因变量值求平均，作为预测值
        return pred      # 返回预测值