用c语言写一个具有过程回放功能的五子棋游戏。
时间: 2024-03-23 17:39:51 浏览: 18
好的,我来为您解答这个问题。
首先,需要使用C语言编写五子棋游戏的基本逻辑,包括棋盘的初始化、落子、判断胜负等等。这里我提供一个简单的示例代码:
```c
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define BOARD_SIZE 15
char board[BOARD_SIZE][BOARD_SIZE];
void init_board() {
for (int i = 0; i < BOARD_SIZE; i++) {
for (int j = 0; j < BOARD_SIZE; j++) {
board[i][j] = '+';
}
}
}
void print_board() {
printf(" ");
for (int i = 0; i < BOARD_SIZE; i++) {
printf("%c ", 'A' + i);
}
printf("\n");
for (int i = 0; i < BOARD_SIZE; i++) {
printf("%2d ", i + 1);
for (int j = 0; j < BOARD_SIZE; j++) {
printf("%c ", board[i][j]);
}
printf("\n");
}
}
int check_win(int x, int y, char player) {
int count = 0;
for (int i = x - 4; i <= x; i++) {
if (i < 0 || i + 4 >= BOARD_SIZE) continue;
count = 0;
for (int j = i; j <= i + 4; j++) {
if (board[j][y] == player) count++;
}
if (count == 5) return 1;
}
for (int j = y - 4; j <= y; j++) {
if (j < 0 || j + 4 >= BOARD_SIZE) continue;
count = 0;
for (int i = j; i <= j + 4; i++) {
if (board[x][i] == player) count++;
}
if (count == 5) return 1;
}
for (int i = x - 4, j = y - 4; i <= x && j <= y; i++, j++) {
if (i < 0 || j < 0 || i + 4 >= BOARD_SIZE || j + 4 >= BOARD_SIZE) continue;
count = 0;
for (int k = 0; k < 5; k++) {
if (board[i+k][j+k] == player) count++;
}
if (count == 5) return 1;
}
for (int i = x + 4, j = y - 4; i >= x && j <= y; i--, j++) {
if (i >= BOARD_SIZE || j < 0 || i - 4 < 0 || j + 4 >= BOARD_SIZE) continue;
count = 0;
for (int k = 0; k < 5; k++) {
if (board[i-k][j+k] == player) count++;
}
if (count == 5) return 1;
}
return 0;
}
void play_game() {
int turn = 0;
int x, y;
char player = 'X';
char buf[256];
init_board();
while (1) {
system("clear");
printf("Turn %d\n", turn + 1);
print_board();
printf("%c's turn: ", player);
fgets(buf, sizeof(buf), stdin);
sscanf(buf, "%c%d", &y, &x);
x--;
y -= 'A';
if (x < 0 || x >= BOARD_SIZE || y < 0 || y >= BOARD_SIZE) {
printf("Invalid input, try again.\n");
continue;
}
if (board[x][y] != '+') {
printf("That spot is already taken, try again.\n");
continue;
}
board[x][y] = player;
if (check_win(x, y, player)) {
system("clear");
printf("Turn %d\n", turn + 1);
print_board();
printf("%c wins!\n", player);
break;
}
turn++;
if (turn == BOARD_SIZE * BOARD_SIZE) {
system("clear");
printf("Turn %d\n", turn + 1);
print_board();
printf("It's a tie!\n");
break;
}
player = player == 'X' ? 'O' : 'X';
}
}
int main() {
play_game();
return 0;
}
```
这段代码实现了一个简单的五子棋游戏,玩家可以通过输入坐标来落子,程序会自动判断胜负并结束游戏。
接下来,需要实现过程回放功能。为了实现这个功能,我们需要记录每一步的落子情况,然后在回放时按照记录的顺序重新落子即可。
这里我提供一个简单的实现思路:
1. 在 `play_game()` 函数中添加一个数组 `history` 来记录每一步的落子情况。
```c
char history[BOARD_SIZE * BOARD_SIZE][3];
int history_count = 0;
```
2. 在每次落子时将落子情况记录到 `history` 数组中。
```c
sprintf(history[history_count], "%c%d", y + 'A', x + 1);
history_count++;
```
3. 添加一个新函数 `replay_game()` 来实现回放功能。
```c
void replay_game() {
init_board();
for (int i = 0; i < history_count; i++) {
int x, y;
sscanf(history[i], "%c%d", &y, &x);
x--;
y -= 'A';
board[x][y] = i % 2 == 0 ? 'X' : 'O';
system("clear");
printf("Replay %d\n", i + 1);
print_board();
sleep(1);
}
}
```
这个函数会根据 `history` 数组中记录的落子情况重新落子,并每次间隔一秒钟以便观察。
最后,在 `play_game()` 函数中添加一个选项,让玩家选择是否回放游戏。
```c
printf("Play again? (y/n): ");
fgets(buf, sizeof(buf), stdin);
if (buf[0] == 'n' || buf[0] == 'N') break;
printf("Replay game? (y/n): ");
fgets(buf, sizeof(buf), stdin);
if (buf[0] == 'y' || buf[0] == 'Y') {
replay_game();
break;
}
```
这样,一个具有过程回放功能的五子棋游戏就完成了。完整代码如下: