生产者消费者问题的嵌入式操作系统代码
时间: 2023-08-06 16:12:02 浏览: 46
生产者消费者问题是一个经典的同步问题,它可以用来模拟多个线程间的协作。在嵌入式操作系统中,可以使用信号量(Semaphore)或互斥锁(Mutex)等同步原语来实现生产者消费者问题。下面是一个使用互斥锁实现的示例代码:
```C
#include <stdio.h>
#include <pthread.h>
#define BUFFER_SIZE 10
int buffer[BUFFER_SIZE];
int count = 0;
pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER;
pthread_cond_t cond_producer = PTHREAD_COND_INITIALIZER;
pthread_cond_t cond_consumer = PTHREAD_COND_INITIALIZER;
void* producer(void* arg) {
int i;
for (i = 0; i < 100; i++) {
pthread_mutex_lock(&mutex);
while (count == BUFFER_SIZE) {
pthread_cond_wait(&cond_producer, &mutex);
}
buffer[count++] = i;
printf("Producer produced %d\n", i);
pthread_cond_signal(&cond_consumer);
pthread_mutex_unlock(&mutex);
}
return NULL;
}
void* consumer(void* arg) {
int i, data;
for (i = 0; i < 100; i++) {
pthread_mutex_lock(&mutex);
while (count == 0) {
pthread_cond_wait(&cond_consumer, &mutex);
}
data = buffer[--count];
printf("Consumer consumed %d\n", data);
pthread_cond_signal(&cond_producer);
pthread_mutex_unlock(&mutex);
}
return NULL;
}
int main() {
pthread_t tid_producer, tid_consumer;
pthread_create(&tid_producer, NULL, producer, NULL);
pthread_create(&tid_consumer, NULL, consumer, NULL);
pthread_join(tid_producer, NULL);
pthread_join(tid_consumer, NULL);
return 0;
}
```
在这个示例中,我们定义了一个大小为 10 的缓冲区,生产者线程不断往缓冲区中添加数据,直到缓冲区满了;消费者线程不断从缓冲区中取出数据,直到缓冲区为空。当缓冲区满了时,生产者线程会等待消费者消费;当缓冲区为空时,消费者线程会等待生产者生产。通过互斥锁和条件变量的配合,我们实现了多个线程的同步操作,避免了竞态条件和死锁等问题的发生。