a=input() b=int((a) print(list1=[len(b),sum(a.[0],a.[1],a.[2],...,a[len(b)-1])])
时间: 2023-12-25 22:02:37 浏览: 26
看起来你的代码有一些语法错误,我来帮你修改一下:
```python
a = input()
b = int(a)
list1 = [len(a), sum(int(x) for x in a)]
print(list1)
```
这段代码可以实现你想要的功能,它的思路是将输入的字符串a转换成整数b,然后用len函数求出a的长度,即位数。最后用sum函数和列表推导式求出a中所有数字的和,即各位数字之和。
你可以将这段代码保存为一个.py文件并运行,输入一个正整数N,就可以得到它的位数及各位数字之和。
相关问题
while True: n=int(input()) a=list(map(int,input().split())) sum=0 a.sort() for i in range(0,len(a)-1): sum+=a[i]*(len(a)-i-1) m=sum/n print('%.2f'%m)转为java代码
```
import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
while (true) {
int n = scanner.nextInt();
if (n == 0) {
break;
}
int[] a = new int[n];
for (int i = 0; i < n; i++) {
a[i] = scanner.nextInt();
}
Arrays.sort(a);
double sum = 0;
for (int i = 0; i < n - 1; i++) {
sum += a[i] * (n - i - 1);
}
double m = sum / n;
System.out.printf("%.2f\n", m);
}
}
}
```
n = input() list = list(n) s = 0 for i in range(len(list)): s += int(list[i]) print(s)
This code takes an input string and converts it to a list of individual characters. It then iterates through each character in the list and converts it to an integer, storing it in the variable "s". However, the variable "s" is overwritten with each iteration, so it only stores the last integer in the list.
To fix this, you could add each integer to a sum variable instead of storing it in "s". Here's the corrected code:
n = input()
lst = list(n)
sum = 0
for i in range(len(lst)):
sum += int(lst[i])
print(sum)
This code will iterate through each character in the list and add its integer value to the sum variable. At the end, it will print the sum of all the integers in the input string.
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