单链表操作实现getelem_【数据结构】单链表的基本操作（C语言

好的，以下是单链表操作实现getelem的C语言代码示例：

#include <stdio.h>
#include <stdlib.h>

// 定义单链表结构体
typedef struct node {
    int data;
    struct node* next;
} Node;

// 创建单链表
Node* createList(int arr[], int n) {
    Node* head = NULL;
    Node* tail = NULL;
    for (int i = 0; i < n; i++) {
        Node* node = (Node*)malloc(sizeof(Node));
        node->data = arr[i];
        node->next = NULL;
        if (head == NULL) {
            head = node;
            tail = node;
        } else {
            tail->next = node;
            tail = node;
        }
    }
    return head;
}

// 获取单链表指定位置的元素值
int getElem(Node* head, int position) {
    int i = 0;
    Node* curr = head;
    while (curr != NULL && i < position) {
        curr = curr->next;
        i++;
    }
    if (curr == NULL) {
        printf("Error: position out of range.\n");
        return -1;
    } else {
        return curr->data;
    }
}

int main() {
    int arr[] = {1, 2, 3, 4, 5};
    int n = sizeof(arr) / sizeof(arr[0]);
    Node* head = createList(arr, n);

    printf("The list: ");
    Node* curr = head;
    while (curr != NULL) {
        printf("%d ", curr->data);
        curr = curr->next;
    }
    printf("\n");

    printf("The element at position 2 is %d.\n", getElem(head, 2));
    printf("The element at position 5 is %d.\n", getElem(head, 5));

    return 0;
}

输出结果为：

The list: 1 2 3 4 5 
The element at position 2 is 3.
Error: position out of range.
The element at position 5 is -1.

以上代码实现了单链表的基本操作之一：获取指定位置的元素值。在 `getElem` 函数中，我们使用了一个循环遍历链表，依次访问每个节点，直到找到目标位置对应的节点，然后返回该节点的数据值。如果目标位置超出了链表的范围，我们输出错误信息并返回 -1。