请写一段火柴人跑酷代码

以下是一个基于Python的简单火柴人跑酷游戏代码：

import pygame
import random

# 初始化 Pygame
pygame.init()

# 设置屏幕大小
screen_width = 800
screen_height = 600
screen = pygame.display.set_mode((screen_width, screen_height))

# 设置游戏标题
pygame.display.set_caption("Stickman Parkour")

# 设置字体
font = pygame.font.SysFont(None, 30)

# 设置火柴人
stickman_image = pygame.image.load("stickman.png")
stickman_width = 50
stickman_height = 50
stickman_x = 100
stickman_y = 450
stickman_y_velocity = 0

# 设置障碍物
obstacle_width = 50
obstacle_height = 50
obstacle_x = screen_width
obstacle_y = 450

# 设置得分
score = 0

# 游戏循环
while True:
    # 处理事件
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            quit()
        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_SPACE:
                stickman_y_velocity = -10

    # 移动火柴人
    stickman_y += stickman_y_velocity
    stickman_y_velocity += 1
    if stickman_y > 450:
        stickman_y = 450
        stickman_y_velocity = 0

    # 移动障碍物
    obstacle_x -= 5
    if obstacle_x < -obstacle_width:
        obstacle_x = screen_width
        obstacle_y = random.randint(350, 450)
        score += 1

    # 绘制屏幕
    screen.fill((255, 255, 255))
    screen.blit(stickman_image, (stickman_x, stickman_y))
    pygame.draw.rect(screen, (255, 0, 0), (obstacle_x, obstacle_y, obstacle_width, obstacle_height))
    score_text = font.render("Score: " + str(score), True, (0, 0, 0))
    screen.blit(score_text, (10, 10))
    pygame.display.update()

运行该代码，即可在 Pygame 窗口中看到一个简单的火柴人跑酷游戏，玩家需要通过按下空格键使火柴人跳过障碍物。