用C语言创建一个单链表

好的，以下是用C语言创建一个单链表的代码：

#include <stdio.h>
#include <stdlib.h>

struct Node {
    int data;
    struct Node* next;
};

struct Node* createNode(int data) {
    struct Node* newNode = (struct Node*)malloc(sizeof(struct Node));
    newNode->data = data;
    newNode->next = NULL;
    return newNode;
}

void insertNode(struct Node** head, int data) {
    struct Node* newNode = createNode(data);
    if (*head == NULL) {
        *head = newNode;
        return;
    }
    struct Node* current = *head;
    while (current->next != NULL) {
        current = current->next;
    }
    current->next = newNode;
}

void printList(struct Node* head) {
    while (head != NULL) {
        printf("%d ", head->data);
        head = head->next;
    }
}

int main() {
    struct Node* head = NULL;
    insertNode(&head, 1);
    insertNode(&head, 2);
    insertNode(&head, 3);
    insertNode(&head, 4);
    printf("The linked list is: ");
    printList(head);
    return 0;
}

这段代码可以创建一个单链表，并打印出链表中的所有元素。