1、数组打印斐波那契数列

好的，这个问题我可以回答。以下是一个打印斐波那契数列的数组代码：

def fibonacci(n):
    if n <= 0:
        return []
    elif n == 1:
        return [1]
    elif n == 2:
        return [1, 1]
    else:
        fib_list = [1, 1]
        for i in range(2, n):
            fib_list.append(fib_list[i-1] + fib_list[i-2])
        return fib_list

print(fibonacci(10))

这个代码可以打印出前10个斐波那契数列。

相关问题

1、数组打印斐波那契数列c++

Sure, I can help you with that! Here's some code to print the Fibonacci sequence in an array using C:

#include <stdio.h>

int main() {
    int n, i;
    printf("Enter the number of terms in the Fibonacci sequence: ");
    scanf("%d", &n);
    
    int fib[n];
    fib[0] = 0;
    fib[1] = 1;
    for(i = 2; i < n; i++) {
        fib[i] = fib[i-1] + fib[i-2];
    }
    
    printf("The Fibonacci sequence is: ");
    for(i = 0; i < n; i++) {
        printf("%d ", fib[i]);
    }
    printf("\n");
    
    return 0;
}

I hope that helps!

数组打印斐波那契数列c++

好的，这是一个关于编程的问题。以下是用 C 语言打印斐波那契数列的代码：

#include <stdio.h>

int main() {
    int n, i;
    int fib[100];

    printf("请输入要打印的斐波那契数列的项数：\n");
    scanf("%d", &n);

    fib[0] = 0;
    fib[1] = 1;

    for (i = 2; i < n; i++) {
        fib[i] = fib[i-1] + fib[i-2];
    }

    printf("斐波那契数列的前 %d 项为：\n", n);
    for (i = 0; i < n; i++) {
        printf("%d ", fib[i]);
    }
    printf("\n");

    return 0;
}

希望能够帮到您！