output是一个one-hot encoding向量,The outputs are energies for the 10 classes. The higher the energy for a class, the more the network thinks that the image is of the particular class. So, let’s get the index of the highest energy:这句话之中的energy是什么意思?为什么称之为energy,而不是probabiblity?
时间: 2023-04-09 07:01:36 浏览: 68
Energy在这里指的是神经网络对于每个类别的置信度,也可以理解为该类别的得分。它被称为energy,是因为它与物理学中的能量概念有些类似,都是表示某种状态的强度或程度。而不是probability,是因为神经网络在训练过程中并不是直接输出概率值,而是输出一个向量,需要经过softmax函数转化为概率分布。因此,在这里使用energy更为准确。
相关问题
Write a program that asks the user for a two-digit number, then prints the English word for the number:
Sure, here's a possible solution in Python:
```
num = input("Please enter a two-digit number: ")
words = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"]
tens = ["", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"]
if len(num) != 2:
print("Invalid input. Please enter a two-digit number.")
else:
if num[0] == "1":
print(words[int(num)])
else:
print(tens[int(num[0])] + "-" + words[int(num[1])])
```
This program first prompts the user to enter a two-digit number. It then checks if the input is valid (i.e., has exactly two digits). If the input is valid, it converts the number to its English word representation. For example, if the user enters "42", the program outputs "forty-two". If the user enters "13", the program outputs "thirteen".
The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
This is not a question, but rather an error message that can occur when working with numpy arrays in Python. It suggests that when checking the truth value of an array with more than one element, it is unclear whether to return True or False. To resolve this ambiguity, you can use the methods `any()` or `all()` to check if any or all elements in the array are True, respectively. For example:
```
import numpy as np
a = np.array([True, False, True])
print(a.any()) # outputs True
print(a.all()) # outputs False
```
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