n = int(input()) list1 = [] for i in range(0,n+1): list1[i] = input() list1.sort() print(list1[0])
时间: 2024-03-23 13:42:51 浏览: 43
这段代码存在问题,会导致程序运行时出现 IndexError 异常。原因在于,列表 list1 在初始化时并没有预留 n+1 个元素的空间,因此在往列表中添加元素时会发生越界错误。正确的代码应该是这样的:
```
n = int(input())
list1 = []
for i in range(n):
list1.append(input())
list1.sort()
print(list1[0])
```
这个代码片段的作用是读入 n 个字符串并将它们按字典序升序排列,最后输出字典序最小的那个字符串。
相关问题
n = input() list = list(n) s = 0 for i in range(len(list)): s += int(list[i]) print(s)
This code takes an input string and converts it to a list of individual characters. It then iterates through each character in the list and converts it to an integer, storing it in the variable "s". However, the variable "s" is overwritten with each iteration, so it only stores the last integer in the list.
To fix this, you could add each integer to a sum variable instead of storing it in "s". Here's the corrected code:
n = input()
lst = list(n)
sum = 0
for i in range(len(lst)):
sum += int(lst[i])
print(sum)
This code will iterate through each character in the list and add its integer value to the sum variable. At the end, it will print the sum of all the integers in the input string.
def primelist(n):for i in range(2,n+1):m=int(i**0.5)for j in range(2,m+1):if i%j==0:breakelse:【1】if name=='main':n=eval(input())for i in 【2】:print(i, end=' ')补全代码
好的,这里是完整的代码:
```
def primelist(n):
for i in range(2,n+1):
m = int(i**0.5)
for j in range(2,m+1):
if i%j==0:
break
else:
print(i, end=' ')
if __name__=='__main__':
n = eval(input())
for i in range(2, n+1):
primelist(i)
print()
```
这个代码会输出从2到n之间的所有素数,每行输出一些素数,不同行之间用空行分隔。