C语言实现：【问题描述】 用带头结点的单链表存储一帧数据，计算该帧数据的累加值作为校验码，倒序输出链表，并将校验码附加在数据帧尾部 【输入形式】 5 9 3 8 4 1 【输出形式】 1 4 8 3 9 5 25 6 1 4 8 3 9 25 【样例输入】 5 9 3 8 4 1 【样例输出】 1 4 8 3 9 5 25 6 1 4 8 3 9 25

好的，对于你的问题，这里提供一份C语言的实现代码，实现了倒序输出链表并将校验码附加在数据帧尾部的功能：

#include <stdio.h>
#include <stdlib.h>

typedef struct Node {
    int data;
    struct Node *next;
} Node, *LinkedList;

LinkedList createList(int n) {
    LinkedList head = (LinkedList) malloc(sizeof(Node));
    head->next = NULL;
    LinkedList p = head;
    for (int i = 0; i < n; i++) {
        int x;
        scanf("%d", &x);
        LinkedList newNode = (LinkedList) malloc(sizeof(Node));
        newNode->data = x;
        newNode->next = NULL;
        p->next = newNode;
        p = newNode;
    }
    return head;
}

int calcChecksum(LinkedList list) {
    int sum = 0;
    LinkedList p = list->next;
    while (p != NULL) {
        sum += p->data;
        p = p->next;
    }
    return sum;
}

void appendChecksum(LinkedList list, int checksum) {
    LinkedList p = list;
    while (p->next != NULL) {
        p = p->next;
    }
    LinkedList newNode = (LinkedList) malloc(sizeof(Node));
    newNode->data = checksum;
    newNode->next = NULL;
    p->next = newNode;
}

void reversePrintList(LinkedList list) {
    if (list->next != NULL) {
        reversePrintList(list->next);
        printf("%d ", list->next->data);
    }
}

void printList(LinkedList list) {
    LinkedList p = list->next;
    while (p != NULL) {
        printf("%d ", p->data);
        p = p->next;
    }
}

int main() {
    int n, checksum;
    scanf("%d", &n);
    LinkedList list = createList(n);
    checksum = calcChecksum(list);
    appendChecksum(list, checksum);
    printf("%d ", n + 1);
    reversePrintList(list);
    printf("%d\n", checksum);
    return 0;
}

以上代码实现了根据输入的数据，创建带头结点的单链表，并计算该帧数据的累加值作为校验码。然后，将校验码附加在数据帧尾部，并倒序输出链表。希望可以帮助到你！