用python求解恶魔与农夫问题
时间: 2023-08-11 15:04:44 浏览: 61
以下是使用Python求解恶魔与农夫问题的代码,采用的是广度优先搜索算法:
```python
from collections import deque
def is_valid(state):
if state[0] != state[1] and state[1] == state[2]:
return False
if state[3] != state[4] and state[4] == state[5]:
return False
return True
def bfs():
start = (3, 3, 1, 0, 0, 0) # 初始状态
target = (0, 0, 0, 3, 3, 1) # 目标状态
queue = deque()
queue.append(start)
visited = set()
visited.add(start)
while queue:
cur_state = queue.popleft()
if cur_state == target:
return True
for i in range(6):
if cur_state[2] == 1 and i == 2:
continue # 农夫不能单独过河
if cur_state[5] == 1 and i == 5:
continue # 农夫不能单独回来
new_state = list(cur_state)
if new_state[2] == 1:
new_state[i] -= 1
else:
new_state[i] += 1
if tuple(new_state) in visited:
continue
if not is_valid(new_state):
continue
queue.append(tuple(new_state))
visited.add(tuple(new_state))
return False
if bfs():
print("找到了一种方案!")
else:
print("不存在可行方案!")
```
在该代码中,is_valid(state)函数用于判断状态state是否合法,bfs()函数用于使用广度优先搜索算法找到符合条件的状态,如果找到了一种方案,则返回True,否则返回False。在主函数中,调用bfs()函数,并根据返回结果输出相应的信息。