TypeError: _make_request() got multiple values for argument 'timeout'
时间: 2024-04-07 09:28:06 浏览: 22
这个错误通常是因为在调用`_make_request()`函数时,传递了多个值给`timeout`参数。请检查一下调用`_make_request()`函数的代码,看看是否传递了多个值给`timeout`参数,如果有,请修改代码,确保只传递一个值给`timeout`参数即可。如果问题仍然存在,请提供更多的代码和上下文信息,以便我能够更好地帮助你。
相关问题
TypeError: __init__() got multiple values for argument 'filters'
This error occurs when the `__init__()` method of a class is called with multiple values for the same argument.
For example, if you have a class `MyClass` with an `__init__()` method that takes a `filters` argument:
```
class MyClass:
def __init__(self, filters):
self.filters = filters
```
And you create an instance of this class and pass multiple values for `filters`:
```
my_instance = MyClass(filters='value1', filters='value2')
```
You will get the `TypeError: __init__() got multiple values for argument 'filters'` error.
To fix this error, make sure that you are only passing one value for each argument in the `__init__()` method. In the above example, you could pass a list of values for `filters` instead:
```
my_instance = MyClass(filters=['value1', 'value2'])
```
TypeError: __init__() got multiple values for argument 'strides'
This error occurs when you pass multiple values for the same argument in the initialization of an object or function.
For example, if you have a class that takes in a 'strides' argument in its __init__() method and you pass multiple values for 'strides' like this:
```
class MyClass:
def __init__(self, strides):
self.strides = strides
my_object = MyClass(strides=2, strides=3)
```
You will get the TypeError: __init__() got multiple values for argument 'strides'
To fix this error, make sure you are passing only one value for each argument. In the example above, you can fix the error by passing only one value for 'strides':
```
my_object = MyClass(strides=2)
```