帮我写一个五子棋游戏可以人机对战
时间: 2023-08-28 10:39:02 浏览: 52
好的,我可以给你提供一个五子棋游戏的 Python 代码,可以实现人机对战的功能。代码如下:
```python
import random
# 初始化棋盘
def init_board():
board = [['+' for _ in range(15)] for _ in range(15)]
return board
# 打印棋盘
def print_board(board):
print(' ', end='')
for i in range(15):
print(chr(i+97), end=' ')
print()
for i in range(15):
print('%2d ' % (i+1), end='')
for j in range(15):
print(board[i][j], end=' ')
print()
# 判断胜负
def check_win(board, row, col, player):
# 判断横向是否连成五子
count = 0
for j in range(col-4, col+1):
if j < 0 or j+4 >= 15:
continue
if board[row][j] == player and board[row][j+1] == player and board[row][j+2] == player and board[row][j+3] == player and board[row][j+4] == player:
return True
# 判断纵向是否连成五子
for i in range(row-4, row+1):
if i < 0 or i+4 >= 15:
continue
if board[i][col] == player and board[i+1][col] == player and board[i+2][col] == player and board[i+3][col] == player and board[i+4][col] == player:
return True
# 判断左上到右下是否连成五子
for i in range(row-4, row+1):
for j in range(col-4, col+1):
if i < 0 or i+4 >= 15 or j < 0 or j+4 >= 15:
continue
if board[i][j] == player and board[i+1][j+1] == player and board[i+2][j+2] == player and board[i+3][j+3] == player and board[i+4][j+4] == player:
return True
# 判断左下到右上是否连成五子
for i in range(row+4, row-1, -1):
for j in range(col-4, col+1):
if i < 0 or i+4 >= 15 or j < 0 or j+4 >= 15:
continue
if board[i][j] == player and board[i-1][j+1] == player and board[i-2][j+2] == player and board[i-3][j+3] == player and board[i-4][j+4] == player:
return True
return False
# 人类玩家下棋
def human_player(board, player):
while True:
move = input('请%s输入您的下棋位置(例如a1):' % player)
if len(move) != 2 or not move[0].isalpha() or not move[1].isdigit():
print('输入不合法,请重新输入!')
continue
col = ord(move[0]) - ord('a')
row = int(move[1:]) - 1
if col < 0 or col >= 15 or row < 0 or row >= 15:
print('输入不合法,请重新输入!')
continue
if board[row][col] != '+':
print('此位置已经有棋子,请重新输入!')
continue
board[row][col] = player
return
# 机器玩家下棋
def ai_player(board, player):
moves = []
for i in range(15):
for j in range(15):
if board[i][j] == '+':
moves.append((i, j))
if len(moves) == 0:
return
row, col = random.choice(moves)
board[row][col] = player
# 主函数
def main():
board = init_board()
print_board(board)
human = input('请选择您执黑棋还是白棋(输入B或W):')
human = human.upper()
if human != 'B' and human != 'W':
print('输入不合法,程序退出!')
return
computer = 'B' if human == 'W' else 'W'
while True:
human_player(board, human)
print_board(board)
if check_win(board, row, col, human):
print('恭喜,您获胜了!')
break
ai_player(board, computer)
print_board(board)
if check_win(board, row, col, computer):
print('很遗憾,您输了!')
break
if __name__ == '__main__':
main()
```
以上代码可以实现一个基本的五子棋游戏,支持人机对战。其中 `human_player` 函数实现人类玩家下棋的功能,`ai_player` 函数实现机器玩家下棋的功能。在主函数中,先让玩家选择执黑棋还是白棋,然后循环让玩家和机器下棋,直到有一方获胜或者棋盘上没有空位。