将新月,上弦月,下弦月,满月时月球、太阳、地球的相对位置绘制到平面坐标图中(太阳在坐标原点处),并分别输出,输出结果为四张图,python代码
时间: 2023-10-09 07:04:22 浏览: 94
这个问题需要对上一个问题的代码进行改进,增加判断新月、上弦月、下弦月和满月的条件,然后分别绘制四张图。以下是代码示例:
```python
import math
import matplotlib.pyplot as plt
# 月球轨道半径
lunar_radius = 384400
# 地球公转周期
earth_period = 365.2425
# 朔望周期
synodic_period = 29.530589
# 太阳半径
sun_radius = 696340
# 计算相对位置
def calculate_position(t):
# 计算月球的位置
lunar_angle = 2 * math.pi * t / synodic_period
lunar_x = lunar_radius * math.sin(lunar_angle)
lunar_y = lunar_radius * math.cos(lunar_angle)
# 计算地球的位置
earth_angle = 2 * math.pi * t / earth_period
earth_x = lunar_radius * math.sin(earth_angle)
earth_y = lunar_radius * math.cos(earth_angle)
return (earth_x - lunar_x, earth_y - lunar_y)
# 绘制图形
def draw_phase(phase):
fig, ax = plt.subplots()
# 绘制太阳
ax.scatter(0, 0, s=sun_radius, color='yellow')
# 绘制月球和地球
for t in range(0, int(synodic_period)):
x, y = calculate_position(t)
lunar_phase = (t / synodic_period - 0.25) % 1
if phase == 'new' and lunar_phase < 0.01:
ax.scatter(x, y, s=10, color='black')
ax.set_title('New Moon')
elif phase == 'first' and lunar_phase < 0.51 and lunar_phase > 0.49:
ax.scatter(x, y, s=10, color='red')
ax.set_title('First Quarter Moon')
elif phase == 'full' and lunar_phase > 0.99:
ax.scatter(x, y, s=10, color='orange')
ax.set_title('Full Moon')
elif phase == 'last' and lunar_phase < 0.51 and lunar_phase > 0.49:
ax.scatter(-x, -y, s=10, color='blue')
ax.set_title('Last Quarter Moon')
# 设置坐标轴
ax.set_aspect('equal')
ax.set_xlim(-lunar_radius, lunar_radius)
ax.set_ylim(-lunar_radius, lunar_radius)
plt.show()
# 绘制四个相位的图形
draw_phase('new')
draw_phase('first')
draw_phase('full')
draw_phase('last')
```
这段代码中,新增了一个 `draw_phase` 函数来绘制每个相位的图形。在循环中,使用 `lunar_phase` 变量计算当前时刻的月相值,然后根据不同的相位条件来绘制相应的图形,并设置标题。最后调用 `draw_phase` 函数分别绘制四个相位的图形。
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