Text text1 = new Text(centerX - 5, centerY - clockRadius + 12, "12"); Text text2 = new Text(centerX - clockRadius + 3, centerY + 5, "9"); Text text3 = new Text(centerX + clockRadius - 10, centerY + 3, "3"); Text text4 = new Text(centerX - 3, centerY + clockRadius - 3, "6")；得出其他的刻度

可以根据时钟的刻度数，用循环语句来创建其他刻度。例如，如果时钟有60个刻度，可以按照以下方式创建刻度：

int numPoints = 60;
int angleStep = 360 / numPoints;

for (int i = 1; i <= numPoints; i++) {
    double angle = i * angleStep;
    double x = centerX + clockRadius * Math.sin(Math.toRadians(angle));
    double y = centerY - clockRadius * Math.cos(Math.toRadians(angle));
    Text text = new Text(x, y, Integer.toString(i));
}

这段代码会创建60个刻度，每个刻度之间相隔6度，从1到60编号。可以根据需要调整刻度的数量和编号方式。

相关问题

Text text1 = new Text(centerX - 5, centerY - clockRadius + 12, "12"); Text text2 = new Text(centerX - clockRadius + 3, centerY + 5, "9"); Text text3 = new Text(centerX + clockRadius - 10, centerY + 3, "3"); Text text4 = new Text(centerX - 3, centerY + clockRadius - 3, "6")；圆心为（150，150），得出其他的九个刻度的坐标

假设时钟一共有12个刻度，包括四个已知刻度，那么可以按照以下方式计算其他8个刻度的坐标：

int numPoints = 12;
int angleStep = 360 / numPoints;

double[] xCoords = new double[numPoints];
double[] yCoords = new double[numPoints];

for (int i = 0; i < numPoints; i++) {
    double angle = i * angleStep;
    double x = centerX + clockRadius * Math.sin(Math.toRadians(angle));
    double y = centerY - clockRadius * Math.cos(Math.toRadians(angle));
    xCoords[i] = x;
    yCoords[i] = y;
}

Text[] texts = new Text[numPoints];
texts[0] = new Text(xCoords[0] - 5, yCoords[0] - clockRadius + 12, "12");
texts[1] = new Text(xCoords[3] - clockRadius + 3, yCoords[3] + 5, "9");
texts[2] = new Text(xCoords[6] + clockRadius - 10, yCoords[6] + 3, "3");
texts[3] = new Text(xCoords[9] - 3, yCoords[9] + clockRadius - 3, "6");

for (int i = 4; i < numPoints; i++) {
    double x = xCoords[i];
    double y = yCoords[i];
    String text = Integer.toString(i + 1);
    texts[i] = new Text(x, y, text);
}

这段代码会创建12个刻度，其中前4个已知，后8个通过计算得到。如果需要更改刻度数量，可以调整 `numPoints` 变量的值，并相应地调整已知刻度的位置和编号。

case 5: //圆 radius = abs(p_point1.x - p_point2.x) / 2; centerX = min(p_point1.x, p_point2.x) + radius; centerY = min(p_point1.y, p_point2.y) + radius; du.Ellipse(centerX - radius, centerY - radius, centerX + radius, centerY + radius); pGraph = new P_Picture(pchoice, p_color, p_brush, p_point1, p_point2); m_ptrArray.Add(pGraph);你能否修改case5之后的代码来实现一种新的绘画出圆的方法

当然可以，以下是一个实现绘画空心圆的新代码：

case 5:
    // 空心圆
    radius = abs(p_point1.x - p_point2.x) / 2;
    centerX = min(p_point1.x, p_point2.x) + radius;
    centerY = min(p_point1.y, p_point2.y) + radius;
    du.Ellipse(centerX - radius, centerY - radius, centerX + radius, centerY + radius);
    pGraph = new P_Picture(pchoice, p_color, p_brush, p_point1, p_point2);
    m_ptrArray.Add(pGraph);

    // 绘制空心圆的边框
    CPen pen(PS_SOLID, 1, p_color);
    CPen *oldPen = du.SelectObject(&pen);
    CBrush *oldBrush = du.SelectStockObject(NULL_BRUSH);
    du.Ellipse(centerX - radius, centerY - radius, centerX + radius, centerY + radius);
    du.SelectObject(oldPen);
    du.SelectObject(oldBrush);
    break;

在原有代码的基础上，我们添加了绘制空心圆边框的部分。具体思路是，我们创建一个实心的画刷 NULL_BRUSH，将其选入画板中，创建一个与画笔颜色相同的画笔 pen，将其选入画板中，然后再次使用 du.Ellipse() 函数绘制圆即可。最后需要将原来的画刷和画笔恢复回去，否则可能会对后续的绘画产生影响。