已知电力系统中节点1为平衡节点,节点4为PV节点,节点2、3为PQ节点,变压器两侧的电压等级分别为 10kV和 110kV。已知:Ù=1.0520°,P=0.5,U=1.1, Zz=0.08+j0.4,Z3=0.12+j0.5,Zz3=0.1+j0.4,Z=j0.3。S;=100MVA,V=V,负荷及支路阻抗S2=0.6+j0.25,S3=0.25+j0.1,编写详细的matlab潮流计算程序。
时间: 2024-03-23 20:38:28 浏览: 198
以下是一个简单的matlab潮流计算程序,根据输入的参数计算每个节点的电压和功率流量。其中,变量Ybus是节点导纳矩阵,PQ节点和PV节点的注入功率和电压是已知的,通过迭代求解未知节点的电压和功率流量。
```matlab
% 输入电力系统参数
Zz = 0.08 + j*0.4;
Z3 = 0.12 + j*0.5;
Zz3 = 0.1 + j*0.4;
Z = j*0.3;
Sbase = 100e6;
Vbase = 110e3;
V1 = Vbase;
V4 = 10e3;
theta1 = 0;
theta4 = 0;
P4 = 0.5*Sbase;
U2 = 1.1;
U3 = 1.1;
S2 = 0.6 + j*0.25;
S3 = 0.25 + j*0.1;
% 计算节点导纳矩阵
Y11 = 1/(Zz + Z/2) + 1/(Z3 + Zz3/2);
Y12 = -1/(Zz + Z/2);
Y13 = -1/(Z3 + Zz3/2);
Y14 = 0;
Y21 = -1/(Zz + Z/2);
Y22 = 1/(Zz + Z/2) + 1/Z;
Y23 = 0;
Y24 = -1/Z;
Y31 = -1/(Z3 + Zz3/2);
Y32 = 0;
Y33 = 1/(Z3 + Zz3/2) + 1/Z;
Y34 = -1/Z;
Y41 = 0;
Y42 = -1/Z;
Y43 = -1/Z;
Y44 = 1/Z;
Ybus = [Y11 Y12 Y13 Y14;
Y21 Y22 Y23 Y24;
Y31 Y32 Y33 Y34;
Y41 Y42 Y43 Y44];
% 初始化迭代变量
V = [V1; U2; U3; V4];
P = [0; -real(S2)/Sbase; -real(S3)/Sbase; P4/Sbase];
Q = [0; -imag(S2)/Sbase; -imag(S3)/Sbase; 0];
iter = 0;
max_iter = 100;
tolerance = 1e-6;
% 迭代求解节点电压和功率流量
while iter < max_iter
iter = iter + 1;
% 计算注入电流
I = conj(Ybus*V);
% 更新节点电压
for n = 2:3
V(n) = U(n)*exp(1j*theta(n));
end
% 更新未知节点的注入功率和电压
P(1) = real(V(1)*conj(I(1)));
Q(1) = imag(V(1)*conj(I(1)));
U(4) = abs(V(4));
theta(4) = angle(V(4));
P(4) = real(V(4)*conj(I(4)));
Q(4) = imag(V(4)*conj(I(4)));
% 判断收敛条件
max_error = max(abs([P; Q]));
if max_error < tolerance
break
end
end
% 输出结果
fprintf('节点电压和功率流量:\n');
fprintf('V1 = %.4f < %.4f\n', abs(V(1)), rad2deg(angle(V(1))));
fprintf('V2 = %.4f < %.4f\n', abs(V(2)), rad2deg(angle(V(2))));
fprintf('V3 = %.4f < %.4f\n', abs(V(3)), rad2deg(angle(V(3))));
fprintf('V4 = %.4f < %.4f\n', abs(V(4)), rad2deg(angle(V(4))));
fprintf('P1 = %.4f MW\n', P(1)*Sbase/1e6);
fprintf('P4 = %.4f MW\n', P(4)*Sbase/1e6);
fprintf('Q1 = %.4f MVar\n', Q(1)*Sbase/1e6);
fprintf('Q4 = %.4f MVar\n', Q(4)*Sbase/1e6);
```
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