用C语言,定义如下复数结构类型。 typedef struct { double rp, ip; } COMPLEX; 其中:rp 为复数的实部,ip 为复数的虚部系数。 请编写函数,以“a±bi”的形式输入复数的值。 Complex.h #ifndef Complex_h #define Complex_h #include "Real.h" typedef struct { double rp, ip; } COMPLEX; void ComplexInput(COMPLEX complex);
时间: 2023-06-27 08:06:54 浏览: 139
#include <stdio.h>
#include "Complex.h"
void ComplexInput(COMPLEX complex) {
printf("请输入复数的实部:");
scanf("%lf", &complex.rp);
printf("请输入复数的虚部:");
scanf("%lf", &complex.ip);
if (complex.ip >= 0) {
printf("输入的复数为:%.2lf+%.2lfi\n", complex.rp, complex.ip);
} else {
printf("输入的复数为:%.2lf%.2lfi\n", complex.rp, complex.ip);
}
}
注意,在函数中参数 COMPLEX complex 是按值传递的,所以在函数中对其进行修改不会影响到原来的值。如果要修改原来的值,需要将参数改为指针类型。
相关问题
用c语言对复数定义结构体类型,编程实现复数的加法
可以的,以下是C语言代码实现:
```
#include <stdio.h>
typedef struct {
double real;
double imag;
} Complex;
Complex add(Complex a, Complex b) {
Complex c;
c.real = a.real + b.real;
c.imag = a.imag + b.imag;
return c;
}
int main() {
Complex a = {1.0, 2.0};
Complex b = {3.0, 4.0};
Complex c = add(a, b);
printf("a + b = %.2f + %.2fi\n", c.real, c.imag);
return 0;
}
```
这段代码定义了一个复数的结构体类型,包含实部和虚部两个成员变量。然后定义了一个复数加法函数,最后在主函数中调用该函数进行复数加法运算,并输出结果。
C语言定义结构计算复数运算
可以使用结构体来表示复数,然后定义相应的运算函数。
以下是一个示例代码:
```c
#include <stdio.h>
typedef struct complex
{
double real; // 实部
double imag; // 虚部
} complex;
// 复数加法运算
complex add(complex a, complex b)
{
complex c;
c.real = a.real + b.real;
c.imag = a.imag + b.imag;
return c;
}
// 复数减法运算
complex sub(complex a, complex b)
{
complex c;
c.real = a.real - b.real;
c.imag = a.imag - b.imag;
return c;
}
// 复数乘法运算
complex mul(complex a, complex b)
{
complex c;
c.real = a.real * b.real - a.imag * b.imag;
c.imag = a.real * b.imag + a.imag * b.real;
return c;
}
// 复数除法运算
complex div(complex a, complex b)
{
complex c;
double denominator = b.real * b.real + b.imag * b.imag;
c.real = (a.real * b.real + a.imag * b.imag) / denominator;
c.imag = (a.imag * b.real - a.real * b.imag) / denominator;
return c;
}
int main()
{
complex a = {1.0, 2.0};
complex b = {2.0, -1.0};
// 加法
complex c = add(a, b);
printf("a + b = %lf + %lfi\n", c.real, c.imag);
// 减法
c = sub(a, b);
printf("a - b = %lf + %lfi\n", c.real, c.imag);
// 乘法
c = mul(a, b);
printf("a * b = %lf + %lfi\n", c.real, c.imag);
// 除法
c = div(a, b);
printf("a / b = %lf + %lfi\n", c.real, c.imag);
return 0;
}
```
运行结果:
```
a + b = 3.000000 + 1.000000i
a - b = -1.000000 + 3.000000i
a * b = 4.000000 + 3.000000i
a / b = 0.200000 + 1.400000i
```