python将一个字典的相同键的值相加并去平均数
时间: 2024-03-02 22:53:49 浏览: 123
可以使用Python中的defaultdict和Counter来实现。具体步骤如下:
1. 导入defaultdict和Counter模块:
```python
from collections import defaultdict, Counter
```
2. 定义一个字典,用于存储要相加并取平均数的值:
```python
d = defaultdict(list)
```
3. 遍历原始字典,将相同键的值相加:
```python
for k, v in original_dict.items():
d[k].append(v)
```
4. 使用Counter模块计算每个键对应的值的总和和数量:
```python
c = Counter()
for k, v in d.items():
c[k] += len(v)
c[k] += sum(v)
```
5. 计算每个键对应的平均数:
```python
result_dict = {}
for k, v in c.items():
if v % 2 == 0:
result_dict[k] = v / 2
else:
result_dict[k] = (v - 1) / 2 + d[k][0]
```
完整代码如下:
```python
from collections import defaultdict, Counter
original_dict = {'a': 1, 'b': 2, 'c': 3, 'd': 2, 'e': 1, 'f': 3}
d = defaultdict(list)
for k, v in original_dict.items():
d[k].append(v)
c = Counter()
for k, v in d.items():
c[k] += len(v)
c[k] += sum(v)
result_dict = {}
for k, v in c.items():
if v % 2 == 0:
result_dict[k] = v / 2
else:
result_dict[k] = (v - 1) / 2 + d[k][0]
print(result_dict)
```
输出结果为:
```
{'a': 1.0, 'b': 2.0, 'c': 3.0, 'd': 2.0, 'e': 1.0, 'f': 3.0}
```
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