编写代码实现剪刀、石头、布的猜举消戏,玩家轴入1、2、3表示剪刀、石头、布,

好的，以下是 Python 3 的代码实现：

import random

def get_computer_choice():
    return random.randint(1, 3)

def get_player_choice():
    while True:
        player_choice = input("请出拳：1.剪刀 2.石头 3.布\n")
        if player_choice in ['1', '2', '3']:
            return int(player_choice)
        else:
            print("请出正确的拳！")

def get_result(computer_choice, player_choice):
    if computer_choice == player_choice:
        return "平局"
    elif (computer_choice == 1 and player_choice == 3) or (computer_choice == 2 and player_choice == 1) or (computer_choice == 3 and player_choice == 2):
        return "你输了"
    else:
        return "你赢了"

def play():
    while True:
        computer_choice = get_computer_choice()
        player_choice = get_player_choice()
        print("电脑出拳：%d" % computer_choice)
        result = get_result(computer_choice, player_choice)
        print(result)
        if result != "平局":
            break

play()

通过上述代码，我们可以实现了一个简单的剪刀石头布游戏。你可以通过输入数字1、2、3来进行游戏，电脑会随机出拳，最终展示出胜负结果。