写出2048游戏的Python代码
时间: 2023-08-31 07:28:30 浏览: 91
### 回答1:
2048 游戏是一款由 Gabriele Cirulli 创建的经典游戏,它的目标是通过滑动网格中的数字方块,使得相同数字的方块在合并时相加,最终达到 2046 或更高的分数。
下面是一个使用 Python 实现 2048 游戏的示例代码:
```
class Game:
def __init__(self, rows, cols):
self.rows = rows
self.cols = cols
self.grid = [[0 for _ in range(cols)] for _ in range(rows)]
self.add_random_tile()
self.add_random_tile()
def add_random_tile(self):
empty_cells = [(i, j) for i in range(self.rows) for j in range(self.cols) if self.grid[i][j] == 0]
if not empty_cells:
return False
i, j = empty_cells[randint(0, len(empty_cells) - 1)]
self.grid[i][j] = 2 if randint(0, 1) else 4
return True
def transpose(self):
self.grid = [[self.grid[j][i] for j in range(self.rows)] for i in range(self.cols)]
def flip(self):
self.grid = [self.grid[i][::-1] for i in range(self.rows)]
def move_left(self):
moved = False
for i in range(self.rows):
row = self.merge_left(self.grid[i])
moved = moved or (row != self.grid[i])
self.grid[i] = row
return moved
def move_right(self):
self.flip()
moved = self.move_left()
self.flip()
return moved
def move_up(self):
self.transpose()
moved = self.move_left()
self.transpose()
return moved
def move_down(self):
self.transpose()
moved = self.move_right()
self.transpose()
return moved
def merge_left(self, row):
merged = [0 for _ in range(self.cols)]
i = 0
for j in range(self.cols):
if row[j] == 0:
continue
if i > 0 and merged[i - 1] == row[j]:
merged[i - 1] *= 2
else:
merged[i] = row[j]
i += 1
return merged
def game_over(self):
if any(self.move_left()) or any(self.move_up()):
### 回答2:
2048是一款益智类的游戏,目标是将相同数字的方块合并,直到达到2048。以下是一个用Python实现的简单版本的2048游戏代码示例:
```python
import random
# 初始化游戏面板
board = [[0] * 4 for _ in range(4)]
# 随机生成一个数字
def generate_number():
# 80%的概率生成2,20%的概率生成4
return 2 if random.random() < 0.8 else 4
# 在空白位置随机生成一个数字
def add_number():
empty_tiles = [(i, j) for i in range(4) for j in range(4) if board[i][j] == 0]
if empty_tiles:
x, y = random.choice(empty_tiles)
board[x][y] = generate_number()
# 判断游戏是否结束
def is_game_over():
for i in range(4):
for j in range(4):
if board[i][j] == 0: # 存在空白位置时游戏未结束
return False
if i > 0 and board[i][j] == board[i-1][j]: # 横向存在相邻相同数字时游戏未结束
return False
if j > 0 and board[i][j] == board[i][j-1]: # 纵向存在相邻相同数字时游戏未结束
return False
return True
# 游戏主循环
while True:
add_number()
# 打印游戏面板
for i in range(4):
for j in range(4):
print(board[i][j], end=' ')
print()
if is_game_over():
print("游戏结束!")
break
direction = input("请输入移动方向(w/a/s/d):") # 根据输入移动方向更新游戏面板
# 根据输入移动方向更新游戏面板...(略)
```
这个示例代码实现了2048游戏的核心逻辑,包括生成数字、添加数字、判断游戏是否结束等功能。在游戏主循环中,首先会随机添加一个新数字,并打印当前游戏面板。然后判断游戏是否结束,如果结束则打印提示信息并退出循环。接下来会要求用户输入移动方向,并根据输入更新游戏面板。其中的移动方向输入的逻辑还需要进一步完善。
### 回答3:
2048是一款益智类的数字游戏,在4x4的方格中滑动方向键,相同数字的方块会相互叠加,最终目标是得到一个数字为2048的方块。下面是一个简单的Python代码实现2048游戏:
```python
import random
import curses
# 初始化屏幕
stdscr = curses.initscr()
# 关闭屏幕回显
curses.noecho()
# 设置输入不需要回车并开启方向键模式
stdscr.keypad(True)
# 设置延迟时间
curses.halfdelay(1)
# 初始化游戏界面
def init_game():
game_board = [[0 for x in range(4)] for y in range(4)]
add_random_tile(game_board)
add_random_tile(game_board)
return game_board
# 随机生成新方块
def add_random_tile(game_board):
tiles = [2, 4]
row, col = random.randint(0, 3), random.randint(0, 3)
while game_board[row][col] != 0:
row, col = random.randint(0, 3), random.randint(0, 3)
game_board[row][col] = random.choice(tiles)
# 绘制游戏界面
def draw_game(game_board):
stdscr.clear()
stdscr.addstr("2048游戏\n")
for row in game_board:
stdscr.addstr(" ".join(str(tile) for tile in row) + "\n")
stdscr.refresh()
# 检查游戏是否结束
def is_game_over(game_board):
for row in game_board:
if 2048 in row:
return True
return False
# 根据方向键滑动
def move(game_board, direction):
new_board = [row[:] for row in game_board]
if direction == 'up':
game_board = transpose(game_board)
new_board = transpose(new_board)
elif direction == 'down':
game_board = transpose(game_board)
new_board = transpose(new_board)
new_board = reverse(new_board)
elif direction == 'right':
new_board = reverse(new_board)
for row in range(4):
new_board[row] = merge(new_board[row])
for row in range(4):
for col in range(4):
game_board[row][col] = new_board[row][col]
if direction == 'up':
game_board = transpose(game_board)
elif direction == 'down':
game_board = transpose(game_board)
game_board = reverse(game_board)
elif direction == 'right':
game_board = reverse(game_board)
return game_board
# 转置方阵
def transpose(game_board):
return [list(row) for row in zip(*game_board)]
# 反转方阵
def reverse(game_board):
return [row[::-1] for row in game_board]
# 合并方块
def merge(row):
new_row = [tile for tile in row if tile != 0]
for i in range(len(new_row) - 1):
if new_row[i] == new_row[i + 1]:
new_row[i] *= 2
new_row.pop(i + 1)
new_row.append(0)
new_row += [0] * (4 - len(new_row))
return new_row
# 游戏结束,退出游戏
def game_over():
curses.nocbreak()
stdscr.keypad(False)
curses.echo()
curses.endwin()
quit()
# 游戏主循环
def game_loop():
game_board = init_game()
draw_game(game_board)
while True:
key = stdscr.getch()
if key == ord('q'):
game_over()
elif key == curses.KEY_UP:
game_board = move(game_board, 'up')
elif key == curses.KEY_DOWN:
game_board = move(game_board, 'down')
elif key == curses.KEY_LEFT:
game_board = move(game_board, 'left')
elif key == curses.KEY_RIGHT:
game_board = move(game_board, 'right')
add_random_tile(game_board)
draw_game(game_board)
if is_game_over(game_board):
# 游戏结束,显示分数
stdscr.addstr("游戏结束!得分:" + str(sum([sum(row) for row in game_board])))
stdscr.refresh()
curses.napms(3000) # 3秒后退出游戏
game_over()
# 运行游戏
game_loop()
```
这是一个基于curses库实现的简单的2048游戏,玩家通过方向键滑动,按q键退出游戏。游戏界面会实时显示方块的变化,并在游戏结束时展示分数。
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