使用turtle库、time库编程实现七段数码管数字时钟
时间: 2024-03-20 18:02:31 浏览: 88
好的,以下是使用Turtle库和Time库编写的Python程序,实现七段数码管数字时钟:
```python
import turtle
import time
# 定义数字对应的七段数码管状态
digit_states = {
0: [1, 1, 1, 1, 1, 1, 0],
1: [0, 1, 1, 0, 0, 0, 0],
2: [1, 1, 0, 1, 1, 0, 1],
3: [1, 1, 1, 1, 0, 0, 1],
4: [0, 1, 1, 0, 0, 1, 1],
5: [1, 0, 1, 1, 0, 1, 1],
6: [1, 0, 1, 1, 1, 1, 1],
7: [1, 1, 1, 0, 0, 0, 0],
8: [1, 1, 1, 1, 1, 1, 1],
9: [1, 1, 1, 1, 0, 1, 1]
}
# 定义画七段数码管的函数
def draw_digit(digit, color):
turtle.pendown() if digit_states[digit][0] else turtle.penup()
turtle.left(90)
turtle.forward(40)
turtle.right(90)
turtle.pendown() if digit_states[digit][1] else turtle.penup()
turtle.forward(20)
turtle.right(90)
turtle.pendown() if digit_states[digit][2] else turtle.penup()
turtle.forward(20)
turtle.right(90)
turtle.pendown() if digit_states[digit][3] else turtle.penup()
turtle.forward(20)
turtle.left(90)
turtle.pendown() if digit_states[digit][4] else turtle.penup()
turtle.forward(20)
turtle.left(90)
turtle.pendown() if digit_states[digit][5] else turtle.penup()
turtle.forward(20)
turtle.left(90)
turtle.pendown() if digit_states[digit][6] else turtle.penup()
turtle.forward(20)
turtle.right(180)
turtle.penup()
turtle.forward(20)
turtle.left(90)
turtle.forward(40)
turtle.right(90)
# 设置画布和画笔
turtle.setup(800, 600)
turtle.speed(0)
turtle.hideturtle()
turtle.penup()
turtle.goto(-150, 0)
# 循环绘制数字时钟
while True:
# 获取当前时间
current_time = time.strftime("%H%M%S", time.localtime())
# 清空画布
turtle.clear()
# 绘制数字时钟
for i, digit in enumerate(current_time):
turtle.color("red")
if i == 2: # 冒号
turtle.penup()
turtle.forward(40)
turtle.pendown()
turtle.circle(10)
turtle.penup()
turtle.backward(40)
turtle.right(90)
turtle.forward(40)
turtle.left(90)
else: # 数字
draw_digit(int(digit), "red")
# 刷新画布
turtle.update()
# 暂停一秒钟
time.sleep(1)
```
运行这个程序,将会在窗口中显示出一个七段数码管数字时钟,每秒钟更新一次。
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