重写一个类型为template<typename K, typename V>的map模板类和迭代器

好的，这是一个很有挑战性的问题，需要一定的C++编程经验。以下是一个简单的实现，希望能够满足你的需求。

#include <iostream>
#include <vector>

template<typename K, typename V>
class Map {
private:
    struct Node {
        K key;
        V value;
        Node* left;
        Node* right;
        Node(K k, V v): key(k), value(v), left(nullptr), right(nullptr) {}
    };
    Node* root;
public:
    Map(): root(nullptr) {}
    ~Map() {
        clear(root);
    }
    void insert(K key, V value) {
        root = insert(root, key, value);
    }
    void erase(K key) {
        root = erase(root, key);
    }
    V& operator[](K key) {
        Node* node = find(root, key);
        if(node == nullptr) {
            node = insert(root, key, V());
        }
        return node->value;
    }
    bool contains(K key) {
        return find(root, key) != nullptr;
    }
    int size() {
        return size(root);
    }
    bool empty() {
        return root == nullptr;
    }
    void clear() {
        clear(root);
        root = nullptr;
    }
private:
    Node* insert(Node* node, K key, V value) {
        if(node == nullptr) {
            return new Node(key, value);
        }
        if(key < node->key) {
            node->left = insert(node->left, key, value);
        }
        else if(key > node->key) {
            node->right = insert(node->right, key, value);
        }
        else {
            node->value = value;
        }
        return node;
    }
    Node* erase(Node* node, K key) {
        if(node == nullptr) {
            return nullptr;
        }
        if(key < node->key) {
            node->left = erase(node->left, key);
        }
        else if(key > node->key) {
            node->right = erase(node->right, key);
        }
        else {
            if(node->left == nullptr) {
                Node* right = node->right;
                delete node;
                return right;
            }
            if(node->right == nullptr) {
                Node* left = node->left;
                delete node;
                return left;
            }
            Node* minNode = findMin(node->right);
            node->key = minNode->key;
            node->value = minNode->value;
            node->right = erase(node->right, minNode->key);
        }
        return node;
    }
    Node* find(Node* node, K key) {
        if(node == nullptr || node->key == key) {
            return node;
        }
        if(key < node->key) {
            return find(node->left, key);
        }
        else {
            return find(node->right, key);
        }
    }
    Node* findMin(Node* node) {
        while(node->left != nullptr) {
            node = node->left;
        }
        return node;
    }
    int size(Node* node) {
        if(node == nullptr) {
            return 0;
        }
        return 1 + size(node->left) + size(node->right);
    }
    void clear(Node* node) {
        if(node == nullptr) {
            return;
        }
        clear(node->left);
        clear(node->right);
        delete node;
    }
public:
    class Iterator {
    private:
        std::vector<Node*> stack;
    public:
        Iterator(Node* root) {
            pushLeft(root);
        }
        Iterator& operator++() {
            Node* node = stack.back();
            stack.pop_back();
            pushLeft(node->right);
            return *this;
        }
        std::pair<const K, V>& operator*() {
            Node* node = stack.back();
            return std::make_pair(node->key, node->value);
        }
        bool operator!=(const Iterator& other) {
            return !stack.empty() || !other.stack.empty() || stack.back() != other.stack.back();
        }
    private:
        void pushLeft(Node* node) {
            while(node != nullptr) {
                stack.push_back(node);
                node = node->left;
            }
        }
    };
    Iterator begin() {
        return Iterator(root);
    }
    Iterator end() {
        return Iterator(nullptr);
    }
};

这个模板类使用了二叉搜索树作为底层数据结构，支持插入、删除、查找、遍历等基本操作。另外，它还实现了一个迭代器类，可以对map进行迭代。

这只是一个简单的实现，你可以根据具体需求进行修改和扩展。希望对你有帮助！