设有一个带头结点的单循环链表，请写出完整代码实现从这个链表中删除值为x的结点。若链表中没有值为x的结点，则打印“没有找到该结点”

### 回答1：

typedef struct Node {
    int data;
    struct Node *next;
} Node, *LinkedList;

void deleteNode(LinkedList L, int x) {
    Node *p = L->next;
    Node *pre = L;
    while (p != L) {
        if (p->data == x) {
            pre->next = p->next;
            free(p);
            printf("删除成功\n");
            return;
        }
        pre = p;
        p = p->next;
    }
    printf("没有找到该结点\n");
}

### 回答2：
以下是完整代码实现从单循环链表中删除值为x的结点的示例代码：

class ListNode:
    def __init__(self, value):
        self.value = value
        self.next = None


def delete_node(head, x):
    if head is None:
        print("没有找到该结点")
        return head

    current = head
    prev = None
    found = False

    # 遍历链表寻找待删除结点
    while True:
        if current.next is head:
            break
        if current.value == x:
            found = True
            break
        prev = current
        current = current.next

    if not found:
        print("没有找到该结点")
        return head

    # 删除结点
    if current is head and current.next is head:  # 链表只有一个结点的处理
        head = None
    elif current is head:  # 待删除结点为头结点的处理
        prev = head
        while prev.next is not head:
            prev = prev.next
        prev.next = current.next
        head = current.next
    else:  # 其他结点的处理
        prev.next = current.next

    return head


# 测试代码
if __name__ == "__main__":
    # 创建一个带头结点的单循环链表
    head = ListNode(None)
    node1 = ListNode(1)
    node2 = ListNode(2)
    node3 = ListNode(3)
    node4 = ListNode(4)
    head.next = node1
    node1.next = node2
    node2.next = node3
    node3.next = node4
    node4.next = head

    # 删除结点值为3的结点
    head = delete_node(head, 3)

    # 打印删除后的链表
    current = head.next
    while current is not head:
        print(current.value, end=" ")
        current = current.next
    print()

该代码实现了在一个带头结点的单循环链表中删除值为x的结点。如果链表中没有值为x的结点，则会打印"没有找到该结点"。

### 回答3：
具体代码如下：

# 定义链表节点类
class Node:
    def __init__(self, value):
        self.value = value
        self.next = None

# 定义循环链表类
class CircularLinkedList:
    def __init__(self):
        self.head = Node(None)
        self.head.next = self.head

    def addNode(self, value):
        newNode = Node(value)
        if self.head.next == self.head:
            self.head.next = newNode
            newNode.next = self.head
        else:
            curNode = self.head.next
            while curNode.next != self.head:
                curNode = curNode.next
            curNode.next = newNode
            newNode.next = self.head

    def deleteNode(self, x):
        if self.head.next == self.head:
            print("没有找到该结点")
            return
        preNode = self.head
        curNode = self.head.next
        while curNode != self.head:
            if curNode.value == x:
                preNode.next = curNode.next
                return
            preNode = curNode
            curNode = curNode.next
        print("没有找到该结点")

    def printList(self):
        if self.head.next == self.head:
            print("链表为空")
            return
        curNode = self.head.next
        while curNode != self.head:
            print(curNode.value, end=" ")
            curNode = curNode.next
        print()

# 测试代码
if __name__ == "__main__":
    linkedList = CircularLinkedList()
    linkedList.printList()  # 链表为空

    linkedList.addNode(1)
    linkedList.addNode(2)
    linkedList.addNode(3)
    linkedList.addNode(4)
    linkedList.printList()  # 1 2 3 4

    linkedList.deleteNode(3)
    linkedList.printList()  # 1 2 4

    linkedList.deleteNode(5)  # 没有找到该结点

该代码首先定义了一个链表节点类Node，包含值和指向下一个节点的指针。然后定义了循环链表类CircularLinkedList，包含头节点和相应的操作方法。其中, `addNode`方法用于向链表中添加节点，`deleteNode`方法用于删除值为x的节点。最后，测试了从链表中删除节点的功能。