sum = 0for i in range(1, 101, 2): sum += 1/i - 1/(i+1)print(sum)
时间: 2024-05-24 14:10:05 浏览: 28
The code calculates the sum of the series 1/1 - 1/3 + 1/5 - 1/7 + ... - 1/99. The variable "sum" is initialized to zero, and then a for loop is used to iterate through the odd numbers from 1 to 101 (exclusive) with a step of 2.
For each iteration, the expression 1/i - 1/(i+1) is evaluated and added to the current value of "sum". This expression calculates the difference between the reciprocal of the current odd number and the reciprocal of the next odd number, and adds it to the sum.
Finally, the loop completes and the value of "sum" is printed. This value represents the sum of the series.
相关问题
sum = 0 for i in range(10): if i // 3 == 2: continue sum = sum + i print(sum)
这段代码是有语法错误的,应该是:
```python
sum = 0
for i in range(10):
if i // 3 == 2:
continue
sum += i
print(sum)
```
这段代码的作用是计算在 0 到 9 的范围内,除以 3 的商等于 2 的数除外,其余数的和。因为当 i // 3 == 2 时,使用 continue 跳过了该循环,所以不会将 i 的值加到 sum 中。最终输出的是符合条件的数的和,即 0 + 1 + 2 + 4 + 5 + 7 + 8 = 27。
sum = 0for i in range(1, 101): sum += iprint(sum)
This Python code will print the sum of integers from 1 to 100, inclusive.
The code first initializes the variable "sum" to 0. It then uses a for loop to iterate through the range of numbers from 1 to 100 (not including 101). During each iteration of the loop, the variable "i" takes on the current value of the loop index.
Inside the loop, the code adds the value of "i" to the current value of "sum". This accumulates the sum of all the numbers from 1 to 100.
After the loop has finished, the code prints out the final value of "sum".
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