上面这个代码我在linux用gcc编译了,但是运行的时候一直在阻塞
时间: 2024-04-08 21:29:56 浏览: 20
非常抱歉,代码中确实存在问题。在条件变量的等待和发送信号之间,需要解锁互斥锁,以便其他线程能够获取互斥锁并发送信号。以下是修正后的代码:
```c
#include <stdio.h>
#include <pthread.h>
pthread_mutex_t mutex;
pthread_cond_t cond_zero, cond_even, cond_odd;
int count = 0;
void* zero(void* arg) {
while (count <= 7) {
pthread_mutex_lock(&mutex);
if (count == 0) {
printf("0");
count++;
pthread_cond_signal(&cond_even);
}
else {
pthread_cond_wait(&cond_zero, &mutex);
}
pthread_mutex_unlock(&mutex);
}
return NULL;
}
void* even(void* arg) {
while (count <= 7) {
pthread_mutex_lock(&mutex);
if (count % 2 == 0 && count != 0) {
printf("%d", count);
count++;
pthread_cond_signal(&cond_odd);
}
else {
pthread_cond_wait(&cond_even, &mutex);
}
pthread_mutex_unlock(&mutex);
}
return NULL;
}
void* odd(void* arg) {
while (count <= 7) {
pthread_mutex_lock(&mutex);
if (count % 2 != 0) {
printf("%d", count);
count++;
pthread_cond_signal(&cond_zero);
}
else {
pthread_cond_wait(&cond_odd, &mutex);
}
pthread_mutex_unlock(&mutex);
}
return NULL;
}
int main() {
pthread_t threads[3];
pthread_mutex_init(&mutex, NULL);
pthread_cond_init(&cond_zero, NULL);
pthread_cond_init(&cond_even, NULL);
pthread_cond_init(&cond_odd, NULL);
pthread_create(&threads[0], NULL, zero, NULL);
pthread_create(&threads[1], NULL, even, NULL);
pthread_create(&threads[2], NULL, odd, NULL);
for (int i = 0; i < 3; i++) {
pthread_join(threads[i], NULL);
}
pthread_mutex_destroy(&mutex);
pthread_cond_destroy(&cond_zero);
pthread_cond_destroy(&cond_even);
pthread_cond_destroy(&cond_odd);
printf("\n");
return 0;
}
```
在修正后的代码中,我们在条件变量的等待和发送信号之间添加了互斥锁的解锁操作(pthread_mutex_unlock)。这样,等待线程在等待期间可以释放互斥锁,允许其他线程获取互斥锁并发送信号。
重新编译并运行代码,应该能够正确地打印出预期的结果。感谢您的指出,并再次对之前的回答中的错误表示歉意。