{ LA: 0.87, LB: 1023.45, LC: 93.23}按照这个格式往下编10个数据 变量名字不变
时间: 2023-06-17 15:07:43 浏览: 60
{ LA: 12.34, LB: 567.89, LC: 43.21}
{ LA: 98.76, LB: 432.10, LC: 76.54}
{ LA: 345.67, LB: 210.54, LC: 10.98}
{ LA: 654.32, LB: 1098.76, LC: 87.65}
{ LA: 21.43, LB: 876.54, LC: 32.10}
{ LA: 987.65, LB: 543.21, LC: 109.87}
{ LA: 1023.45, LB: 93.23, LC: 0.87}
{ LA: 210.98, LB: 76.54, LC: 345.67}
{ LA: 432.10, LB: 12.34, LC: 567.89}
{ LA: 1098.76, LB: 654.32, LC: 21.43}
相关问题
{ LA: 0.87, LB: 1023.45, LA: 93.23} 按照这个格式往下编10个数据 变量名字不变
{ LA: 12.34, LB: 56.78, LA: 90.12}
{ LA: 43.21, LB: 87.65, LA: 76.54}
{ LA: 98.76, LB: 54.32, LA: 21.43}
{ LA: 65.43, LB: 23.45, LA: 87.65}
{ LA: 34.56, LB: 78.90, LA: 43.21}
{ LA: 87.65, LB: 12.34, LA: 56.78}
{ LA: 21.43, LB: 90.12, LA: 98.76}
{ LA: 54.32, LB: 76.54, LA: 65.43}
{ LA: 23.45, LB: 43.21, LA: 34.56}
{ LA: 78.90, LB: 56.78, LA: 87.65}
构造两个带有表头节点的有序单链表La 、Lb. 编写程序实现将La,Lb 合并成一个有序单链表Lc
好的,我可以为您提供代码,以下是实现的Python代码:
```
class Node:
def __init__(self, data=None):
self.data = data
self.next = None
def merge_sorted_lists(la, lb):
dummy_node = Node()
tail = dummy_node
while True:
if la is None:
tail.next = lb
break
if lb is None:
tail.next = la
break
if la.data <= lb.data:
tail.next = la
la = la.next
else:
tail.next = lb
lb = lb.next
tail = tail.next
return dummy_node.next
# Example usage:
la = Node()
la.next = Node(1)
la.next.next = Node(3)
lb = Node()
lb.next = Node(2)
lb.next.next = Node(4)
lc = merge_sorted_lists(la.next, lb.next)
while lc:
print(lc.data)
lc = lc.next
```
希望能够帮到您,如果您还有其他问题需要解答,请随时提出。