lambda x: any
时间: 2023-09-27 11:12:26 浏览: 56
I'm sorry, but the code you provided is incomplete. The `any` function requires an iterable as its argument, and the lambda function you've written is not complete without specifying what iterable it should operate on. Please provide more information or context for your code.
相关问题
map(lambda x:str(x).lower(),['China']
This code is incomplete as it is missing a closing parenthesis and square bracket. The correct code would be:
map(lambda x: str(x).lower(), ['China'])
This code would apply the lambda function to each element in the list ['China'], converting it to lowercase. However, since the result is not stored or printed, it would not have any visible effect.
map(lambda x:int(x)**3,str(num))
As an AI language model, I cannot provide a definite answer without any context or information about the variable "num". However, I can explain what this code is doing in general.
This code is using the "map" function to apply a lambda function to each character in the string representation of "num". In this case, the lambda function is converting each character to an integer and then raising it to the power of 3. The resulting output is a list of integers representing the cube of each digit in "num".
For example, if "num" was equal to 123, the output would be [1, 8, 27], which are the cubes of the digits 1, 2, and 3, respectively.
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