c++输出n行n列的空心倒三角星号*方阵

好的，以下是 C 语言代码实现：

#include <stdio.h>

int main() {
    int n;
    printf("请输入方阵的行数：");
    scanf("%d", &n);

    for (int i = n; i >= 1; i--) {
        for (int j = 1; j < i; j++) {
            printf(" ");
        }
        printf("*");
        for (int k = 1; k <= 2 * (n - i) - 1; k++) {
            printf(" ");
        }
        if (i != 1) {
            printf("*");
        }
        printf("\n");
    }

    return 0;
}

希望能够满足你的要求！

相关问题

n行n列顺时针螺旋方阵c++

下面是一个实现 n 行 n 列顺时针螺旋方阵的 C++ 代码：

#include <iostream>
#include <vector>

using namespace std;

vector<vector<int>> spiralOrder(int n) {
    vector<vector<int>> res(n, vector<int>(n));
    int top = 0, bottom = n - 1, left = 0, right = n - 1;
    int num = 1;
    while (top <= bottom && left <= right) {
        for (int j = left; j <= right; j++) {
            res[top][j] = num++;
        }
        top++;

        for (int i = top; i <= bottom; i++) {
            res[i][right] = num++;
        }
        right--;

        if (top <= bottom) {
            for (int j = right; j >= left; j--) {
                res[bottom][j] = num++;
            }
            bottom--;
        }

        if (left <= right) {
            for (int i = bottom; i >= top; i--) {
                res[i][left] = num++;
            }
            left++;
        }
    }
    return res;
}

int main() {
    int n = 4;
    vector<vector<int>> res = spiralOrder(n);
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            cout << res[i][j] << " ";
        }
        cout << endl;
    }
    return 0;
}

该算法使用了四个指针来控制螺旋方阵的遍历顺序，具体实现可以参考代码注释。

c++倒三角星号列阵

以下是两种C++倒三角星号列阵的例子：

1. 使用三个for循环语句输出倒三角星号列阵：

#include <iostream>
using namespace std;

int main() {
    for (int i = 9; i >= 1; i--) {
        for (int j = 1; j <= 9 - i + 1; j++) {
            cout << " ";
        }
        for (int k = 1; k <= 2 * i - 1; k++) {
            cout << "*";
        }
        cout << endl;
    }
    system("pause");
    return 0;
}

2. 使用四个for循环语句输出倒三角星号列阵：

#include <iostream>
using namespace std;

int main() {
    for (int i = 10; i <= 19; i++) {
        for (int j = 0; j <= i - 10; j++) {
            cout << " ";
        }
        for (int k = 1; k <= 2 * (19 - i) - 1; k++) {
            cout << "*";
        }
        cout << endl;
    }
    system("pause");
    return 0;
}