1. 调用time库,用函数绘制当前时间的7段数码管,要求精确到分钟
时间: 2023-06-02 09:07:07 浏览: 55
好的,这是一个技术问题,我可以帮您回答。以下是实现代码:
```
import time
# 数字对应的7段数码管编码
digit_code = {
0: "1111110",
1: "0110000",
2: "1101101",
3: "1111001",
4: "0110011",
5: "1011011",
6: "1011111",
7: "1110000",
8: "1111111",
9: "1111011"
}
def draw_digit(digit, row):
"""
绘制单个数字的7段数码管
"""
code = digit_code[digit]
if code[0] == "1":
print(" ", end="")
else:
print(" ", end="")
if code[1] == "1":
print("_", end="")
else:
print(" ", end="")
if code[2] == "1":
print(" ", end="")
else:
print(" ", end="")
print("")
if code[5] == "1":
print("|", end="")
else:
print(" ", end="")
print(" ", end="")
if code[6] == "1":
print("|", end="")
else:
print(" ", end="")
print("")
if code[4] == "1":
print(" ", end="")
else:
print(" ", end="")
if code[3] == "1":
print("_", end="")
else:
print(" ", end="")
if code[2] == "1":
print(" ", end="")
else:
print(" ", end="")
print("")
def draw_time():
"""
绘制当前时间的7段数码管
"""
now = time.localtime()
hour = now.tm_hour
minute = now.tm_min
print("当前时间:" + str(hour) + ":" + str(minute))
print(" ", end="")
print(" ", end="")
print(" ", end="")
print(" ", end="")
print(" ")
draw_digit(hour // 10, 1)
draw_digit(hour % 10, 2)
print("------", end="")
print(" ", end="")
print("------", end="")
print(" ", end="")
print("------")
draw_digit(minute // 10, 4)
draw_digit(minute % 10, 5)
print(" ", end="")
print(" ", end="")
print(" ", end="")
print(" ", end="")
print(" ")
if __name__ == "__main__":
draw_time()
```
希望能够帮到您!
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