分别输入2个复数的实部与虚部，用函数实现计算2个复数之和与之积。 若2个复数分别为：c1=x1+(y1)i, c2=x2+(y2)i， 则： c1+c2 = (x1+x2) + (y1+y2)i c1*c2 = (x1*x2-y1*y2) + (x1*y2+x2*y1)i 输入格式: 输入在一行中给出4个实数，分别代表c1和c2的实部和虚部。 输出格式: 在两行中分别输出c1+c2和c1*c2的计算结果。

好的，以下是实现计算2个复数之和与之积的代码：

#include <stdio.h>

typedef struct {
    double real;  // 实部
    double imag;  // 虚部
} Complex;

Complex add(Complex c1, Complex c2);  // 复数加法
Complex multiply(Complex c1, Complex c2);  // 复数乘法

int main() {
    double x1, y1, x2, y2;
    printf("请输入2个复数的实部和虚部：");
    scanf("%lf%lf%lf%lf", &x1, &y1, &x2, &y2);
    Complex c1 = {x1, y1};
    Complex c2 = {x2, y2};
    Complex sum = add(c1, c2);
    Complex mul = multiply(c1, c2);
    printf("c1+c2 = %.2f+%.2fi\n", sum.real, sum.imag);
    printf("c1*c2 = %.2f+%.2fi\n", mul.real, mul.imag);
    return 0;
}

Complex add(Complex c1, Complex c2) {
    Complex sum;
    sum.real = c1.real + c2.real;
    sum.imag = c1.imag + c2.imag;
    return sum;
}

Complex multiply(Complex c1, Complex c2) {
    Complex mul;
    mul.real = c1.real * c2.real - c1.imag * c2.imag;
    mul.imag = c1.real * c2.imag + c2.real * c1.imag;
    return mul;
}

输入格式为：

请输入2个复数的实部和虚部：1 2 3 4

输出格式为：

c1+c2 = 4.00+6.00i
c1*c2 = -5.00+10.00i

希望能帮到你！