1. arr1 = [1,2,3,4,5,6,78,8] 2. arr2 = [1,2,4,5,777,98]实现数组交集并集和差集

好的，针对你的问题，我可以提供以下实现：

1. 数组交集：

arr1 = [1,2,3,4,5,6,78,8]
arr2 = [1,2,4,5,777,98]

intersection = list(set(arr1).intersection(set(arr2)))
print(intersection)

输出结果为：`[1, 2, 4, 5]`

2. 数组并集：

arr1 = [1,2,3,4,5,6,78,8]
arr2 = [1,2,4,5,777,98]

union = list(set(arr1).union(set(arr2)))
print(union)

输出结果为：`[1, 2, 3, 4, 5, 6, 98, 777, 8, 78]`

3. 数组差集：

arr1 = [1,2,3,4,5,6,78,8]
arr2 = [1,2,4,5,777,98]

diff_arr1 = list(set(arr1).difference(set(arr2)))
diff_arr2 = list(set(arr2).difference(set(arr1)))

print("arr1中独有的元素:", diff_arr1)
print("arr2中独有的元素:", diff_arr2)

输出结果为：

arr1中独有的元素: [8, 3, 6, 78]
arr2中独有的元素: [98, 777]

希望我的回答对你有所帮助！