三角函数计算器用栈来写、

您可以使用栈来实现三角函数计算器，以下是一个简单的示例代码：

import math

# 定义操作符优先级
priority = {'+': 1, '-': 1, '*': 2, '/': 2, '^': 3}

# 定义操作符和对应的函数
operators = {
    '+': lambda a, b: a + b,
    '-': lambda a, b: a - b,
    '*': lambda a, b: a * b,
    '/': lambda a, b: a / b,
    '^': lambda a, b: a ** b,
    'sin': lambda a: math.sin(a),
    'cos': lambda a: math.cos(a),
    'tan': lambda a: math.tan(a),
}

def evaluate(expression):
    stack = []
    tokens = expression.split()

    for token in tokens:
        if token in operators:
            if token in {'sin', 'cos', 'tan'}:  # 处理三角函数
                stack.append(token)
            else:
                while stack and stack[-1] in operators and priority[token] <= priority[stack[-1]]:
                    operator = stack.pop()
                    if operator in {'sin', 'cos', 'tan'}:  # 处理三角函数
                        operand = stack.pop()
                        result = operators[operator](operand)
                    else:
                        operand2 = stack.pop()
                        operand1 = stack.pop()
                        result = operators[operator](operand1, operand2)
                    stack.append(result)
                stack.append(token)
        else:
            stack.append(float(token))

    while stack:
        operator = stack.pop()
        if operator in {'sin', 'cos', 'tan'}:  # 处理三角函数
            operand = stack.pop()
            result = operators[operator](operand)
        else:
            operand2 = stack.pop()
            operand1 = stack.pop()
            result = operators[operator](operand1, operand2)
        stack.append(result)

    return stack[0]

# 测试
expression = "sin 30 + cos 45 * 2"
result = evaluate(expression)
print(result)

以上代码实现了一个简单的三角函数计算器，通过使用栈来处理表达式中的操作符和操作数，最终得出计算结果。在处理三角函数时，将函数名和操作数分别入栈，计算时取出操作数进行计算。