C语言计算e=1+1/1！+1/2！+1/3！+……+1/n！

#include <stdio.h>

int main() {
    int n;
    double e = 1.0, f = 1.0;
    printf("请输入n：");
    scanf("%d", &n);
    for (int i = 1; i <= n; i++) {
        f = f * i;
        e += 1 / f;
    }
    printf("e = %lf\n", e);
    return 0;
}

运行结果：

请输入n：10
e = 2.718282