This is described in Chapter 3.4.5 "Error Message".

这是出错的时候弹出来的信息！

信息见附件

报错提示

error message

用c++解决Input The first line contains the number n of fighters in the division (2 ≤ n ≤ 50000). The second line contains ten integers in the range from 1 to 10000 separated with a space written in the nonascending order. These are the times of sending a message from one telegraph to another if the length of their common prefix is zero, one, two, …, nine. The next n lines contain the numbers of telegraphs given to the fighters of the division. The number of Anka's telegraph is described first, and the number of Chapaev's telegraph is described last. All the numbers of telegraphs are different. Output Output the only line “-1” if it is impossible to deliver the message to Chapaev. Otherwise, in the first line output the minimal time required to deliver the message. In the second line output the number of fighters in the delivery path, and in the third line output their numbers separated with a space in the order from Anka to Chapaev. The fighters of the 25th Division are numbered from 1 to n in the order in which their mobile telegraphs are described in the input. If there are several ways to deliver the message in minimal time, output any of them.

下面是使用Dijkstra算法解决该问题的C++代码实现： c++ #include #include #include #include using namespace std; const int INF = 0x3f3f3f3f;...在输出路径时，可以使用一个pre数组记录路径中每个节点的前...

Standard SPI Mode Standard SPI mode is selected when the Mode option in the Vivado IDE is set to Standard. The relevant parameters in this mode are: • Mode • Enable STARTUPE2 Primitive • Transaction Width • No. of Slaves • Frequency Ratio Send Feedback AXI Quad SPI v3.2 7 PG153 April 4, 2018 www.xilinx.com Chapter 1: Overview • Enable FIFO The properties of the core in standard SPI mode, including or excluding a FIFO, are described as: • The choice of inclusion of FIFO is based on the Enable FIFO parameter. FIFO Depth parameter is linked to Enable FIFO parameter. FIFO Depth limits the transmit and receive FIFO depth to 16 or 256 when FIFO is enabled. When FIFO is not enabled, the value of FIFO depth parameter is considered to be 0. A FIFO depth of 256 should be used because this is the most suitable depth in relation to the flash memory page size. • The valid values for the FIFO Depth option in this mode are 16 or 256 when FIFO is enabled through Enable FIFO parameter. When Enable FIFO is 0 and no FIFO is included in the core. Data transmission occurs through the single transmit and receive register. When FIFO Depth is 16 or 256, the transmit or receive FIFO is included in the design with a depth of 16 or 256 elements. The width of the transmit and receive FIFO is configured with the Transaction Width option. The AXI Quad SPI core supports continuous transfer mode. When configured as master, the transfer continues until the data is available in the transmit register/FIFO. This capability is provided in both manual and automatic slave select modes. As an example, during the page read command, the command, address, and number of data beats in the DTR must be set equal to the same number of data bytes intended to be read by the SPI memory. When the core is configured as a slave, if the slave select line (SPISEL) goes High (inactive state) during the data element transfer, the current transfer is aborted. If the slave select line goes Low, the aborted data element is transmitted again. The slave mode of the core is allowed only in the standard SPI mode.

标准SPI模式是在Vivado IDE中将Mode选项设置为Standard时选择的模式。该模式下的相关参数有： • Mode（模式） • Enable STARTUPE2 Primitive（启用STARTUPE2原语） • Transaction Width（传输宽度） ...

Design a java program that reads a file containing a list of integers, and calculates the average of those integers. The program should handle any exceptions that may occur during file input/output or calculation of the average, and provide appropriate error messages to the user. Additionally, the program should allow the user to specify the file name and path as a command line argument when running the program. This program takes a command line argument specifying the file name, path, and reads the file line by line using a BufferedReader. It attempts to parse each line as an integer using Integer.parseInt(), and adds it to a running sum and count. If a line is not a valid integer, it prints an error message but continues processing the rest of the file. If the file is empty or does not contain any valid integers, it prints an error message. Finally, it calculates the average and prints it to the console. The program also handles various exceptions that may occur during file input/output or calculation of the average, and prints appropriate error messages to the user.

Here's an example Java program that meets the requirements you've described: java import java.io.BufferedReader; import java.io.FileReader; import java.io.IOException; public class ...

用中文解释一下：The selection criteria that define the search class C3 reduce the background by introducing a constraint on the signal morphology. In order to illustrate the significance of GW150914 against a background of events with arbitrary shapes, we also show the results of a search that uses the same set of events as the one described above but without this constraint. Specifically, we use only two search classes: the C1 class and the union of C2 and C3 classes (C2 þ C3). In this two-class search the GW150914 event is found in the C2 þ C3 class. The left panel of Fig. 4 shows the C2 þ C3 class results and background. In the background of this class there are four events with ηc ≥ 32.1, yielding a false alarm rate for GW150914 of 1 in 8 400 years. This corresponds to a false alarm probability of 5 × 10−6 equivalent to 4.4σ.

定义搜索类别C3的选择标准通过引入信号形态的约束减少了背景噪声。为了说明GW150914在任意形状事件背景下的显著性，我们还展示了一种使用与上述相同的事件集进行搜索但没有这种约束的搜索结果。...

按照以下要求仅在两个#之间编译该代码As described in the lecture and the optional softmax lab, numerical stability is improved if the softmax is grouped with the loss function rather than the output layer during training. This has implications when building the model and using the model. Building: The final Dense layer should use a 'linear' activation. This is effectively no activation. The model.compile statement will indicate this by including from_logits=True. loss=tf.keras.losses.SparseCategoricalCrossentropy(from_logits=True) This does not impact the form of the target. In the case of SparseCategorialCrossentropy, the target is the expected digit, 0-9. Using the model: The outputs are not probabilities. If output probabilities are desired, apply a softmax function.

Sure, I can help you ...Please note that input_dim and input_data in the code should be replaced with the appropriate values for your specific case. Let me know if you need any further assistance!

Our experimental evaluation includes the following datasets: CIFAR10, CIFAR100-20, STL10 and ImageNet. The ImageNet dataset should be downloaded separately and saved to the path described in utils/mypath.py. Other datasets will be downloaded automatically and saved to the correct path when missing.

这是一段关于实验评估的说明。实验评估使用了 CIFAR10、CIFAR100-20、STL10 和 ImageNet 数据集。其中 ImageNet 数据集需要单独下载并保存到 utils/mypath.py 中指定的路径。其他数据集如果缺失，则会自动下载并保存...

7-3 Score Processing 分数 10 作者翁恺单位浙江大学 Write a program to process students score data. The input of your program has lines of text, in one of the two formats: Student's name and student id, as <student id>, <name>, and Score for one student of one course, as <student id>, <course name>, <marks>. Example of the two formats are: 3190101234, Zhang San 3190101111, Linear Algebra, 89.5 Comma is used as the seperator of each field, and will never be in any of the fields. Notice that there are more than one word for name of the person and name of the course. To make your code easier, the score can be treated as double. The number of the students and the number of the courses are not known at the beginning. The number of lines are not known at the beginning either. The lines of different format appear in no order. One student may not get enrolled in every course. Your program should read every line in and print out a table of summary in .csv format. The first line of the output is the table head, consists fields like this: student id, name, <course name 1>, <course name 2>, ..., average where the course names are all the courses read, in alphabet order. There should be one space after each comma. Then each line of the output is data for one student, in the ascended order of their student id, with score of each course, like: 3190101234, Zhang San, 85.0, , 89.5, , , 87.3 For the course that hasn't been enrolled, leave a blank before the comma, and should not get included in the average. The average has one decimal place. There should be one space after each comma. And the last line of the output is a summary line for average score of every course, like: , , 76.2, 87.4, , , 76.8 All the number output, including the averages have one decimal place. Input Format As described in the text above. Output Format As described in the text above. The standard output is generated by a program compiled by gcc, that the round of the first decimal place is in the "gcc way". Sample Input 3180111435, Operating System, 34.5 3180111430, Linear Algebra, 80 3180111435, Jessie Zhao 3180111430, Zhiwen Yang 3180111430, Computer Architecture, 46.5 3180111434, Linear Algebra, 61.5 3180111434, Anna Teng Sample Output student id, name, Computer Architecture, Linear Algebra, Operating System, average 3180111430, Zhiwen Yang, 46.5, 80.0, , 63.2 3180111434, Anna Teng, , 61.5, , 61.5 3180111435, Jessie Zhao, , , 34.5, 34.5 , , 46.5, 70.8, 34.

很好，这是一道关于学生成绩数据处理的编程题。下面是我的解答： C++ #include #include #include #include #include using namespace std;...这个程序的主要思路是使用四个字典来记录学生姓名、学生成绩、...

Write a program to 1.Setup a simulating backing store in memory. Read the data from pdata.bin to this backing store. 2.Initialize a page table for process p, set the frame number to be -1 for each page, indicating that the page is not loaded into memory yet. 3.Read logical addresses one by one from la.txt. 4.For each logical address, a)if its page has been loaded into physical memory, simply find the frame number in the page table, then generate physical address, find and print out the physical address and data inside this address. b)if the page is used for the first time, i.e., in page table, its frame number is -1，then the page that contains this address should be loaded into a free frame in physical memory (RAM). Then update the page table by adding the frame number to the right index in the page table. Then repeat 4a). Assumption: 1.Assume the file la.txt includes the sequence of generated addresses from CPU. 2.Use a part of memory as backing store that store data for a process. 3.The backing store size is 128 bytes 4.The size of process p is 128 bytes. 5.The contents of p is included in a file pdata.bin which is a binary file. 6.Use a part of memory as RAM. The size of physical memory is 256 bytes, from 0 to 255. All the physical memory is available, allocating starting from beginning in sequence. That is, allocate frame 0 first, then frame 1, then frame 2…. 7.The size of a frame is 32 bytes, i.e., 5 bits for the offset in a frame, total number of frames is 8. At beginning, no page table is available for process p.

Here is a sample program ...Note that this program assumes that there is always at least one free frame in physical memory. If there are no free frames, the program will print an error message and stop.

A bit stream 10011101 is transmitted using the standard CRC method described in the text. The generator polynomial is 1001. Show the actual bit string transmitted.

3. The remainder obtained is 10, which is appended to the end of the original bit stream to create the actual bit string transmitted: 1001110110 Therefore, the actual bit string transmitted is ...

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(完整数据)全国旅游抽样调查数据（2001-2022）

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This is described in Chapter 3.4.5 "Error Message".

Unions are explicitly specified and described in [SOMEIP].

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This is described in Chapter 3.4.5 "Error Message".

Unions are explicitly specified and described in [SOMEIP].

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这是出错的时候弹出来的信息！

报错提示

error message

Our experimental evaluation includes the following datasets: CIFAR10, CIFAR100-20, STL10 and ImageNet. The ImageNet dataset should be downloaded separately and saved to the path described in utils/mypath.py. Other datasets will be downloaded automatically and saved to the correct path when missing.

A bit stream 10011101 is transmitted using the standard CRC method described in the text. The generator polynomial is 1001. Show the actual bit string transmitted.

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