python解四阶数独

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相关问题

python解武士数独

武士数独问题是一个特殊的9x9数独问题。可以将其视为按照左上、右上、中间、左下、右下的顺序，在有解的前提下，能够求解出一个有效解。在Python中，可以使用回溯算法来解决这个问题。回溯算法通过尝试每个可能的数字，并逐步填充数独格子，直到找到一个有效解为止。

以下是一个可能的Python解决方案:

def solve_samurai_sudoku(board):
    if is_complete(board):
        return board

    row, col = find_empty_cell(board)
    for num in range(1, 10):
        if is_valid(board, row, col, num):
            board[row][col] = num
            if solve_samurai_sudoku(board):
                return board
            board[row][col] = 0

    return None

def is_complete(board):
    for row in range(9):
        for col in range(9):
            if board[row][col] == 0:
                return False
    return True

def find_empty_cell(board):
    for row in range(9):
        for col in range(9):
            if board[row][col] == 0:
                return row, col
    return None

def is_valid(board, row, col, num):
    for i in range(9):
        if board[row][i] == num or board[i][col] == num:
            return False

    start_row = 3 * (row // 3)
    start_col = 3 * (col // 3)
    for i in range(start_row, start_row + 3):
        for j in range(start_col, start_col + 3):
            if board[i][j] == num:
                return False

    return True

# 以下是一个示例数独问题的输入和调用示例
sudoku_board = [
    [0, 0, 0, 2, 5, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 7, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 5, 4],
    [0, 0, 0, 8, 0, 0, 0, 3, 0],
    [0, 0, 0, 0, 0, 0, 5, 0, 0],
    [0, 0, 2, 0, 0, 6, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0]
]

solution = solve_samurai_sudoku(sudoku_board)
if solution:
    for row in solution:
        print(row)
else:
    print("No solution found.")

用python写一个数独破解代码

好的，以下是一个简单的数独破解代码：

def print_board(board):
    for i in range(9):
        for j in range(9):
            print(board[i][j], end=" ")
        print()

def find_empty(board):
    for i in range(9):
        for j in range(9):
            if board[i][j] == 0:
                return (i, j)
    return None

def is_valid(board, num, row, col):
    for i in range(9):
        if board[row][i] == num or board[i][col] == num:
            return False
    box_row = (row // 3) * 3
    box_col = (col // 3) * 3
    for i in range(3):
        for j in range(3):
            if board[box_row + i][box_col + j] == num:
                return False
    return True

def solve_board(board):
    empty = find_empty(board)
    if not empty:
        return True
    row, col = empty
    for num in range(1, 10):
        if is_valid(board, num, row, col):
            board[row][col] = num
            if solve_board(board):
                return True
            board[row][col] = 0
    return False

board = [
    [0, 0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0],
    [0, 0, 0, 0, 0, 0, 0, 0, 0]
]

# 填入数独题目
board[0][2] = 4
board[0][5] = 6
board[0][6] = 7
board[1][0] = 3
board[1][1] = 7
board[1][7] = 1
board[2][0] = 6
board[2][2] = 2
board[2][5] = 1
board[2][8] = 9
board[3][4] = 9
board[4][1] = 5
board[4][3] = 1
board[4][5] = 4
board[4][7] = 9
board[5][4] = 7
board[6][0] = 5
board[6][3] = 2
board[6][6] = 3
board[7][1] = 3
board[7][7] = 2
board[8][2] = 1
board[8][3] = 9
board[8][6] = 8

print("数独题目：")
print_board(board)

solve_board(board)

print("解决方案：")
print_board(board)

该代码定义了几个函数：

- `print_board`：用于打印数独面板。
- `find_empty`：查找数独面板上空的位置。
- `is_valid`：检查在给定位置放置数字是否有效。
- `solve_board`：递归解决数独问题。

在主程序中，我们创建了一个9x9的数独面板，并填入了一些数字作为示例。然后，我们调用`solve_board`函数来解决数独问题，并使用`print_board`函数打印解决方案。