select distinct FE.t_job_resume_id,FE.FSchoolName,R.FFirstTime,fe.FEndDate from T_Job_Resume_FEducExpe FE inner join T_Job_Resume R ON R.ID = FE.t_job_resume_id WHERE R.FFirstTime IS not NULL and r.FFirstTime < TO_DATE('2023-7-17','YYYY-MM-DD') AND SUBSTR(FE.FEndDate,0,3) < '2023'

这是一个SQL查询，目的是从两个表中获取一些数据。根据提供的查询条件，查询语句中使用了两个表的内连接（INNER JOIN），并通过ID进行关联。

查询结果将返回以下字段：
- FE.t_job_resume_id：工作简历的ID
- FE.FSchoolName：学校名称
- R.FFirstTime：开始时间
- fe.FEndDate：结束时间

查询条件包括：
- R.FFirstTime IS not NULL：确保开始时间不为空
- r.FFirstTime < TO_DATE('2023-7-17','YYYY-MM-DD')：确保开始时间在指定日期之前
- SUBSTR(FE.FEndDate,0,3) < '2023'：确保结束时间的年份小于2023年

通过执行这个查询，你将得到满足条件的唯一（distinct）记录的结果集。

相关问题

以hive的角度检查语法： with cur_dim_comb as (SELECT DISTINCT t.dim_comb ,t.var_sub_class ,t.acc_value FROM gerp.cux_cst_data_alloc_his t WHERE t.top_var_type = '10' AND t.job_ver_id in (SELECT ver.job_ver_id AS p_job_ver_id FROM gerp.cux_cst_dist_jobs_all job INNER JOIN gerp.cux_cst_dist_jobs_vers_all ver ON job.job_id = ver.job_id )) select tp.bd_code --事业部编码 ,tp.bd_name --事业部名称 ,hp.ou_code --OU名称 ,hp.ou_name --OU编码 ,op.main_class_desc --差异大类 ,op.acc_value --科目代码 ,op.acc_desc --科目名称 ,op.dim_comb --区分维度 ,op.begin_amount --期初余额 ,op.accrual_amount --本期发生 ,op.balance_diff_alloc_amount --期末差异结存 ,op.var_sub_class ,op.main_class_value ,op.org_id ,op.period_name ,op.job_ver_id from (select up.* ,q1.* from (SELECT DISTINCT maincl.* ,t.* FROM t inner join (SELECT fv.flex_value ,fv.description FROM fv inner join fs on fv.flex_value_set_id = fs.flex_value_set_id AND fs.flex_value_set_name = 'CUX_CST_VARIANCE_TYPE' AND fv.enabled_flag = 'Y' AND fv.hierarchy_level = '2' AND fv.flex_value LIKE '10%' ) maincl on t.var_main_class = maincl.flex_value inner join cur_dim_comb on cur_dim_comb.var_sub_class = t.var_sub_class and cur_dim_comb.acc_value = t.acc_value WHERE 1 = 1 AND t.top_var_type = '10' AND t.job_ver_id in (SELECT ver.job_ver_id AS p_job_ver_id FROM gerp.cux_cst_dist_jobs_all job INNER JOIN gerp.cux_cst_dist_jobs_vers_all ver ON job.job_id = ver.job_id) ORDER BY maincl.description ,t.acc_value ,cur_dim_comb.dim_comb ) up inner join (SELECT t1.* ,SUM(t1.begin_amount) begin_amount ,SUM(t1.accrual_amount) accrual_amount ,SUM(t1.balance_diff_alloc_amount) balance_diff_alloc_amount FROM gerp.cux_cst_data_alloc_his t1 LEFT JOIN gerp.cux_cst_data_alloc_his t ON t1.top_var_type = '10' AND t1.var_sub_class = t.var_sub_class --p_var_sub_class AND t1.org_id = t.org_id --p_org_id AND t1.period_name = t.period_name --p_period_name AND t1.job_ver_id = t.job_ver_id --p_job_ver_id AND t1.acc_value = t.acc_value --p_acc_value WHERE t1.dim_comb in (select distinct dim_comb from cur_dim_comb) group by t1.org_id,t1.period_name,t1.job_ver_id,t1.var_sub_class,t1.acc_value ) q1 on q1.org_id = up.org_id --p_org_id AND q1.period_name = up.period_name --p_period_name AND q1.job_ver_id = up.job_ver_id --p_job_ver_id AND q1.var_sub_class = up.var_sub_class --p_var_sub_class AND q1.acc_value = up.acc_value --p_acc_value ) op

从 Hive 的角度来检查语法，以下是您提供的 SQL 查询语句：

with cur_dim_comb as (
    SELECT DISTINCT t.dim_comb, t.var_sub_class, t.acc_value
    FROM gerp.cux_cst_data_alloc_his t
    WHERE t.top_var_type = '10'
    AND t.job_ver_id in (
        SELECT ver.job_ver_id AS p_job_ver_id
        FROM gerp.cux_cst_dist_jobs_all job
        INNER JOIN gerp.cux_cst_dist_jobs_vers_all ver
        ON job.job_id = ver.job_id
    )
)
select
    tp.bd_code, --事业部编码
    tp.bd_name, --事业部名称
    hp.ou_code, --OU名称
    hp.ou_name, --OU编码
    op.main_class_desc, --差异大类
    op.acc_value, --科目代码
    op.acc_desc, --科目名称
    op.dim_comb, --区分维度
    op.begin_amount, --期初余额
    op.accrual_amount, --本期发生
    op.balance_diff_alloc_amount, --期末差异结存
    op.var_sub_class,
    op.main_class_value,
    op.org_id,
    op.period_name,
    op.job_ver_id
from (
    select up.*, q1.*
    from (
        SELECT DISTINCT
            maincl.*,
            t.*
        FROM
            t
            inner join (
                SELECT
                    fv.flex_value,
                    fv.description
                FROM
                    fv
                    inner join fs
                    on fv.flex_value_set_id = fs.flex_value_set_id
                    AND fs.flex_value_set_name = 'CUX_CST_VARIANCE_TYPE'
                    AND fv.enabled_flag = 'Y'
                    AND fv.hierarchy_level = '2'
                    AND fv.flex_value LIKE '10%'
            ) maincl
            on t.var_main_class = maincl.flex_value
            inner join cur_dim_comb
            on cur_dim_comb.var_sub_class = t.var_sub_class
            and cur_dim_comb.acc_value = t.acc_value
        WHERE
            1 = 1
            AND t.top_var_type = '10'
            AND t.job_ver_id in (
                SELECT ver.job_ver_id AS p_job_ver_id
                FROM gerp.cux_cst_dist_jobs_all job
                INNER JOIN gerp.cux_cst_dist_jobs_vers_all ver
                ON job.job_id = ver.job_id
            )
        ORDER BY
            maincl.description,
            t.acc_value,
            cur_dim_comb.dim_comb
    ) up
    inner join (
        SELECT
            t1.*,
            SUM(t1.begin_amount) begin_amount,
            SUM(t1.accrual_amount) accrual_amount,
            SUM(t1.balance_diff_alloc_amount) balance_diff_alloc_amount
        FROM
            gerp.cux_cst_data_alloc_his t1
            LEFT JOIN gerp.cux_cst_data_alloc_his t
            ON t1.top_var_type = '10'
            AND t1.var_sub_class = t.var_sub_class --p_var_sub_class
            AND t1.org_id = t.org_id --p_org_id
            AND t1.period_name = t.period_name --p_period_name
            AND t1.job_ver_id = t.job_ver_id --p_job_ver_id
            AND t1.acc_value = t.acc_value --p_acc_value
        WHERE
            t1.dim_comb in (select distinct dim_comb from cur_dim_comb)
        group by
            t1.org_id,
            t1.period_name,
            t1.job_ver_id,
            t1.var_sub_class,
            t1.acc_value
    ) q1
    on q1.org_id = up.org_id --p_org_id
    AND q1.period_name = up.period_name --p_period_name
    AND q1.job_ver_id = up.job_ver_id --p_job_ver_id
    AND q1.var_sub_class = up.var_sub_class --p_var_sub_class
    AND q1.acc_value = up.acc_value --p_acc_value
) op

从语法角度来看，该查询语句是有效的。但是，如果您想要确保语句完全符合您的预期，请先测试该语句在您的环境中的执行结果。

select distinct S.customer_name from depositor as S where not exists ( (select branch_name from branch where branch_city = 'Brooklyn') except (select R.branch_name from depositor as T, account as R where T.account_number = R.account_number and S.customer_name = T.customer_name ))

这是一个SQL查询语句，其目的是查询在布鲁克林市没有开户的所有客户姓名。

具体解释如下：

1. `select distinct S.customer_name`：选择不同的客户姓名，以避免重复。

2. `from depositor as S`：从“存款人”表中选择数据，并将其别名为“S”。

3. `where not exists`：使用“not exists”关键字执行否定的存在性检查。

4. `( (select branch_name from branch where branch_city = 'Brooklyn') except (select R.branch_name from depositor as T, account as R where T.account_number = R.account_number and S.customer_name = T.customer_name ))`：在布鲁克林市开户的所有分行名称与S客户的分行名称进行比较，如果S客户未在任何一个分行开户，则该记录将被选择。

需要注意的是，这个查询语句的具体实现方式可能因数据库系统的不同而有所不同。