能不能写一个完整的代码

当然可以，以下是一个简化的版本，展示了如何使用C语言实现上述渡口管理算法。请注意，这只是一个基础示例，实际应用中需要根据车辆到达的具体情况（例如输入流）来更新队列。此外，代码没有包含错误处理和边界条件检查，你需要根据实际需求进行完善。

#include <stdio.h>
#include <stdlib.h>

typedef enum {VEHICLE_TYPE_CAR = 0, VEHICLE_TYPE_TRUCK = 1} VehicleType;
typedef struct {
    VehicleType type;
    int count;
} Vehicle;

typedef struct Queue {
    Vehicle *items;
    int front, rear;
    int capacity;
} Queue;

void enqueue(Queue *queue, Vehicle vehicle) {
    if (queue->rear == queue->capacity - 1) {
        printf("Queue is full, cannot enqueue.\n");
        return;
    }
    queue->items[(queue->rear + 1) % queue->capacity].type = vehicle.type;
    queue->items[(queue->rear + 1) % queue->capacity].count = vehicle.count;
    queue->rear = (queue->rear + 1) % queue->capacity;
}

Vehicle dequeue(Queue *queue) {
    if (queue->front == -1) {
        printf("Queue is empty, cannot dequeue.\n");
        return (Vehicle){.type = VEHICLE_TYPE_NONE, .count = 0};
    }
    Vehicle vehicle = queue->items[queue->front];
    queue->items[queue->front] = (Vehicle){.type = VEHICLE_TYPE_NONE, .count = 0};
    queue->front = (queue->front + 1) % queue->capacity;
    return vehicle;
}

int main() {
    Queue ferryQueue = {.front = .rear = -1, .capacity = 10};
    Queue carQueue = {.front = .rear = -1, .capacity = 10};
    Queue truckQueue = {.front = .rear = -1, .capacity = 10};

    // 假设有一个数组存储车辆数据，这里仅作演示
    Vehicle vehicles[] = {
        {VEHICLE_TYPE_CAR, 3},
        {VEHICLE_TYPE_CAR, 2},
        {VEHICLE_TYPE_TRUCK, 1},
        {VEHICLE_TYPE_CAR, 5},
        {VEHICLE_TYPE_TRUCK, 4},
        // 更多车辆...
    };
    int vehicleCount = sizeof(vehicles) / sizeof(vehicles[0]);

    for (int i = 0; i < vehicleCount; ++i) {
        enqueue(&vehicleType, vehicles[i]);
        // 根据车辆类型和数量处理规则
        while (carQueue.count >= 4 && ferryQueue.count < ferryQueue.capacity) {
            Vehicle ferryCar = dequeue(&carQueue);
            enqueue(&ferryQueue, ferryCar);
        }
        if (ferryQueue.count == ferryQueue.capacity) {
            // 渡船满了，将所有车辆送到对岸
            while (ferryQueue.count > 0) {
                Vehicle ferryVehicle = dequeue(&ferryQueue);
                printf("Sending %s vehicle to the other side.\n",
                       ferryVehicle.type == VEHICLE_TYPE_CAR ? "car" : "truck");
            }
        }
    }

    return 0;
}