Python 矩阵转置
时间: 2024-01-15 21:18:42 浏览: 142
矩阵转置是指将矩阵的行和列互换位置,得到一个新的矩阵。在Python中,可以使用多种方法来实现矩阵转置。
1. 使用嵌套列表推导式:
```python
matrix = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
transpose = [[row[i] for row in matrix] for i in range(len(matrix[0]))]
print(transpose)
```
2. 使用zip函数:
```python
matrix = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
transpose = list(zip(*matrix))
print(transpose)
```
3. 使用numpy库:
```python
import numpy as np
matrix = np.array([[1, 2, 3], [4, 5, 6], [7, 8, 9]])
transpose = np.transpose(matrix)
print(transpose)
```
以上是三种常用的Python矩阵转置的方法。
相关问题
python矩阵转置
要将一个矩阵进行转置,可以使用NumPy库中的transpose函数来实现。下面是一个示例代码:
```python
import numpy as np
# 定义一个矩阵
matrix = np.array([[1, 2, 3],
[4, 5, 6],
[7, 8, 9]])
# 使用transpose函数进行转置
transposed_matrix = np.transpose(matrix)
print(transposed_matrix)
```
输出结果为:
```
[[1 4 7]
[2 5 8]
[3 6 9]]
```
Python矩阵转置
以下是三种Python矩阵转置的方法:
1.使用zip函数,将原矩阵的每一列作为新矩阵的每一行:
```python
matrix = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
transpose = [list(x) for x in zip(*matrix)]
print(transpose) # 输出:[[1, 4, 7], [2, 5, 8], [3, 6, 9]]
```
2.使用numpy库中的transpose函数:
```python
import numpy as np
matrix = np.array([[1, 2, 3], [4, 5, 6], [7, 8, 9]])
transpose = np.transpose(matrix)
print(transpose) # 输出:[[1 4 7], [2 5 8], [3 6 9]]
```
3.使用numpy库中的T属性:
```python
import numpy as np
matrix = np.array([[1, 2, 3], [4, 5, 6], [7, 8, 9]])
transpose = matrix.T
print(transpose) # 输出:[[1 4 7], [2 5 8], [3 6 9]]
```
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