AS3游戏编程大学教程

Game
University
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"AS3 Game University 是一本由 Gary Rosenzweig 编著的关于使用 ActionScript 3.0 进行游戏编程的书籍，适用于初学者。本书旨在教授读者如何利用 ActionScript 3.0 这种强大的脚本语言创建互动游戏。" 在《AS3 Game University》中，作者 Gary Rosenzweig 提供了深入浅出的教程，帮助读者掌握 ActionScript 3.0 的基础知识以及在游戏中应用这些知识的实践技巧。ActionScript 3.0 是 Adobe Flash 平台的主要脚本语言，广泛用于创建交互式网页内容、动画和游戏。通过本书，读者可以了解到以下关键知识点： 1. **ActionScript 3.0 基础**：了解 AS3 的语法结构、变量、数据类型、控制流语句（如条件语句和循环）以及函数。 2. **面向对象编程**：AS3 是一个完全支持面向对象编程（OOP）的语言，读者将学习类、对象、封装、继承和多态等概念。 3. **时间轴与帧操作**：学习如何使用时间轴和帧来创建动态内容和动画，理解不同类型的帧（如普通帧、关键帧和空白关键帧）以及动作脚本与帧的关系。 4. **事件处理**：掌握事件监听器和事件处理程序的使用，这是在用户与游戏互动时不可或缺的一部分。 5. **图形与绘图**：学习如何使用AS3的绘图API来创建和修改图形，包括线条、形状和位图。 6. **物理系统**：虽然AS3本身不包含物理引擎，但书可能介绍如何实现简单的物理模拟，如碰撞检测和重力效果。 7. **游戏机制**：探索游戏设计的基本原理，如游戏循环、得分系统、关卡设计和游戏状态管理。 8. **声音与视频处理**：了解如何在AS3中集成音频和视频元素，以增强游戏体验。 9. **网络通信**：如果涉及，可能会讲解如何使用AS3进行基本的网络通信，例如加载外部数据或实现多人在线游戏。 10. **优化与调试**：学习性能优化技巧，以及使用调试工具来查找和修复代码中的错误。 此外，书中还可能包含练习和项目，以帮助读者巩固所学知识，并实际动手制作游戏。由于版权原因，书中具体实例和代码无法在此提供，但读者可以通过购买或合法途径获取该书以获取完整内容。 《AS3 Game University》是一本全面的指南，适合那些希望利用 ActionScript 3.0 技能进入游戏开发领域的初学者。通过本书，读者不仅可以学习到游戏编程的基础，还能掌握制作高质量互动内容所需的技能。

Flash Game University

2009-07-26 上传
《Flash Game University》是一本专为游戏开发者设计的教程，主要关注使用ActionScript 3（AS3）在Flash平台上创建游戏的技术。ActionScript是Adobe Flash Professional和Flash Player中支持的编程语言，它使得...

ActionScript 3.0 Game Programming University教程和源码

2011-10-28 上传
通过《ActionScript 3.0 Game Programming University》教程，你将有机会系统地学习和掌握ActionScript 3.0游戏编程的各项技能，并能够独立完成从简单的互动小游戏到复杂的游戏项目。无论是想成为独立游戏开发者，...

import tkinter as tk import random class Application(tk.Frame): def __init__(self,master=None): super().__init__(master) self.master=master self.pack() self.create_widgets() def create_widgets(self): self.game1_button = tk.Button(self,text=';';game1';';,command=self.game1) self.game1_button.pack(side=';';left';';) self.game2_button = tk.Button(self,text=';';game2';';,command=self.game2) self.game2_button.pack(side=';';left';';) self.game3_button = tk.Button(self,text=';';game3';';,command=self.game3) self.game3_button.pack(side=';';left';';) self.game4_button = tk.Button(self,text=';';game4';';,command=self.game4) self.game4_button.pack(side=';';left';';)

2023-06-11 上传
每个按钮的文本分别为"game1"、"game2"、"game3"、"game4"，并且为每个按钮绑定了对应的游戏函数game1、game2、game3、game4。 需要注意的是，这段代码存在语法错误，应该在导入tkinter库时和在创建Application类时...

import numpy as np import random def generate_game(): """ 生成数独游戏 """ game = np.zeros((9, 9), dtype=int) for i in range(9): for j in range(9): if random.random() < 0.6: game[i][j] = random.randint(1, 9) return gamedef check_game(game): """ 检查数独游戏是否合法 """ for i in range(9): for j in range(9): if game[i][j] == 0: return False for k in range(9): if k != i and game[k][j] == game[i][j]: return False if k != j and game[i][k] == game[i][j]: return False if k != (i % 3 * 3 + j % 3) and game[i // 3 * 3 + k // 3][j // 3 * 3 + k % 3] == game[i][j]: return False return True def input_number(game, i, j): """ 提示用户输入数字 """ while True: number = input("请输入数字(1-9)，输入0表示清空：") if number.isdigit(): number = int(number) if number >= 0 and number <= 9: break game[i][j] = number def main(): """ 主程序 """ game = generate_game() while not check_game(game): game = generate_game() print(game) while True: i = int(input("请输入行号(1-9)：")) - 1 j = int(input("请输入列号(1-9)：")) - 1 input_number(game, i, j) print(game) if check_game(game): print("恭喜您，游戏结束！") break if __name__ == "__main__": main()

2023-06-12 上传
= (i % 3 * 3 + j % 3) and game[i // 3 * 3 + k // 3][j // 3 * 3 + k % 3] == game[i][j]: return False return True def input_number(game, i, j): """ 提示用户输入数字 """ while True: number = ...

代码注释import tkinter as tk from tkinter import * import tkinter.messagebox # 弹窗库 import numpy as np class Game1: def __init__(self, master): self.master = master self.frame = tk.Frame(self.master) self.frame.pack() self.label = tk.Label(self.frame, text="Game 1") self.label.pack() class Game2: def __init__(self, master): self.master = master self.frame = tk.Frame(self.master) self.frame.pack() self.label = tk.Label(self.frame, text="Game 2") self.label.pack() class Game3: def __init__(self, master): self.master = master self.frame = tk.Frame(self.master) self.frame.pack() self.label = tk.Label(self.frame, text="Game 3") self.label.pack() class Login: def __init__(self, master): self.master = master self.frame = tk.Frame(self.master) self.frame.pack() self.username_label = tk.Label(self.frame, text="Username:") self.username_label.pack() self.username_entry = tk.Entry(self.frame) self.username_entry.pack() self.password_label = tk.Label(self.frame, text="Password:") self.password_label.pack() self.password_entry = tk.Entry(self.frame, show="*") self.password_entry.pack() self.game_label = tk.Label(self.frame, text="Select a game:") self.game_label.pack() self.game1_button = tk.Button(self.frame, text="Game 1", command=self.game1) self.game1_button.pack() self.game2_button = tk.Button(self.frame, text="Game 2", command=self.game2) self.game2_button.pack() self.game3_button = tk.Button(self.frame, text="Game 3", command=self.game3) self.game3_button.pack() def game1(self): username = self.username_entry.get() password = self.password_entry.get() # Check if username and password are valid if username == "1" and password == "1": self.frame.destroy() import A #game1 = Game1(self.master) else: # Display error message error_label = tk.Label(self.frame, text="Invalid username or password") error_label.pack() def game2(self): username = self.username_entry.get() password = self.password_entry.get() # Check if username and password are valid if username == "1" and password == "1": self.frame.destroy() import B #game2 = Game2(self.master) else: # Display error message error_label = tk.Label(self.frame, text="Invalid username or password") error_label.pack() def game3(self): username = self.username_entry.get() password = self.password_entry.get() # Check if username and password are valid if username == "1" and password == "1": self.frame.destroy() import C #game3 = Game3(self.master) else: # Display error message error_label = tk.Label(self.frame, text="Invalid username or password") error_label.pack() if __name__ == "__main__": root = tk.Tk() login = Login(root) root.mainloop()

2023-05-31 上传
其中，游戏分为三个，分别是 Game1、Game2 和 Game3。 程序的具体实现如下： 1. 导入 tkinter 库及其相关模块： ```python import tkinter as tk from tkinter import * import tkinter.messagebox # 弹窗库 ...

Implement time_per_word, which takes in times_per_player, a list of lists for each player with timestamps indicating when each player finished typing each word. It also takes in a list words. It returns a game with the given information. A game is a data abstraction that has a list of words and times. The times are stored as a list of lists of how long it took each player to type each word. times[i][j] indicates how long it took player i to type word j. For example, if times_per_player = [[1, 3, 5], [2, 5, 6]], the corresponding time attribute of the game would be [[2, 2], [3, 1]]. Timestamps are cumulative and always increasing, while the values in time are differences between consecutive timestamps. Be sure to use the game constructor when returning a game, rather than assuming a particular data format.

2023-06-01 上传
Finally, we construct a `Game` object using the `Game` constructor, passing in the `words` and `times` as arguments. This ensures that the resulting object has the correct data type and structure.

SELECT t1.gname,t1.tid,t1.gid, t1.score, t1.pics FROM game t1 INNER JOIN ( SELECT tid, MAX(score) AS max_score FROM game WHERE score != '评分过少' GROUP BY tid ) t2 ON t1.tid = t2.tid AND t1.score = t2.max_score INNER JOIN gameType t3 ON t1.tid = t3.tid WHERE t3.tname IN ( SELECT tname FROM user u INNER JOIN stock s ON u.uid = s.uid INNER JOIN game g ON s.gid = g.gid INNER JOIN gameType t ON g.tid = t.tid WHERE u.uid = (SELECT uid FROM user WHERE uname = 'admin') GROUP BY tname ) ORDER BY t1.gid;优化以上sql使其相同的tid只取一条

2023-07-11 上传
ROW_NUMBER() OVER (PARTITION BY tid ORDER BY gid) AS rn FROM game WHERE score != '评分过少' ) t1 INNER JOIN ( SELECT tid, MAX(score) AS max_score FROM game WHERE score != '评分过少' GROUP BY ...

SELECT t1.gname, t1.score, t1.pics FROM game t1 INNER JOIN ( SELECT tid, MAX(score) AS max_score FROM game WHERE score != '评分过少' GROUP BY tid ) t2 ON t1.tid = t2.tid AND t1.score = t2.max_score INNER JOIN gameType t3 ON t1.tid = t3.tid WHERE t3.tname IN ( SELECT tname FROM `user` u INNER JOIN stock s ON u.uid = s.uid INNER JOIN game g ON s.gid = g.gid INNER JOIN gameType t ON g.tid = t.tid WHERE u.uid = (SELECT uid FROM `user` WHERE uname = 'admin') GROUP BY tname ) ORDER BY t1.gid;将以上sql优化，使得查出来的数据，相同的tname只留最小的gid的那一个数据

2023-07-11 上传
SELECT tid, MAX(score) AS max_score, MIN(gid) AS min_gid FROM game WHERE score != '评分过少' GROUP BY tid ) t2 ON t1.tid = t2.tid AND t1.score = t2.max_score AND t1.gid = t2.min_gid INNER JOIN ...

Can you give me some architecture about this game ?

2023-04-04 上传
3. Game World: This is where the game takes place. It includes the environment, characters, objects, and obstacles. 4. Artificial Intelligence (AI): This is responsible for controlling the behavior ...

用textpad写Problem 3: GuessingGame~ Develop an application that allows the user to play a word guessing game. The application should store a secret word. When the game starts the word should be displayed to the user as *'s and then the user should be asked to guess that word one letter at a time. Each time a letter is guessed correctly the display should update with the correct letter. The user should have up to 10 guesses in order to guess the whole word. For example, house would be displayed as *米*米*。Then, if the userentered the letter e, the display would be updated to ****e.一个可实例化类一个主类

2023-05-31 上传
GuessingGame game = new GuessingGame(secretWord); while (!game.isGameOver()) { System.out.println("Current guess: " + game.getCurrentGuess()); System.out.println("Remaining attempts: " + game....
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