解释这段代码if (board_channel_number == 2) { int cnt0 = 0; for (int j = spos*4; cnt0 < cnt && j + 3 < netBuffer.size(); j += 4,cnt0++) { y[0].push_back(static_cast<double>(((netBuffer[j + 0] & 0xFF) | (netBuffer[j + 1] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution))); y[1].push_back(static_cast<double>(((netBuffer[j + 2] & 0xFF) | (netBuffer[j + 3] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution))); } cnt = cnt0;
时间: 2024-04-10 08:30:55 浏览: 63
这段代码是一个条件语句,当`board_channel_number`于2时执行以下操作。代码中首先了一个变量`cnt0`并初始化为。然后使用`for`循环,从pos*4`开始遍历`netBuffer`列表,每次增加4,直到`cnt0`小于`cnt`且`j + 3`小于`netBuffer`的大小为止。
在循环内部,代码执行以下操作:
- 首先,通过位运算和位移操作将`netBuffer[j + 0]`和`netBuffer[j + 1]`合并成一个16位的整数,并乘以`board_input_range[0] * 2 / qPow(2, board_resolution)`,然后转换为`double`类型,并将结果添加到名为`y[0]`的列表中。
- 然后,通过位运算和位移操作将`netBuffer[j + 2]`和`netBuffer[j + 3]`合并成一个16位的整数,并乘以`board_input_range[0] * 2 / qPow(2, board_resolution)`,然后转换为`double`类型,并将结果添加到名为`y[1]`的列表中。
最后,将`cnt0`的值赋给`cnt`,以便在循环外部可以使用。
相关问题
逐句解释这段代码if (board_channel_number == 2) { int cnt0 = 0; for (int j = spos*4; cnt0 < cnt && j + 3 < netBuffer.size(); j += 4,cnt0++) { y[0].push_back(static_cast<double>(((netBuffer[j + 0] & 0xFF) | (netBuffer[j + 1] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution))); y[1].push_back(static_cast<double>(((netBuffer[j + 2] & 0xFF) | (netBuffer[j + 3] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution))); } cnt = cnt0;
这段代码首先判断变量`board_channel_number`是否等于2。如果满足条件,就执行接下来的代码块。
在代码块中,首先声明了一个整型变量`cnt0`并初始化为0。然后使用一个循环,循环变量`j`从`spos*4`开始,直到`cnt0`小于`cnt`并且`j + 3`小于`netBuffer.size()`为止,每次循环增加4。
循环体内部有两个语句。第一个语句将`netBuffer[j + 0]`和`netBuffer[j + 1]`的值合并,并进行一系列的乘法和除法计算,最后将结果转换为`double`类型,并添加到`y[0]`容器中。第二个语句同样进行了类似的操作,将合并后的值添加到`y[1]`容器中。
最后,将`cnt0`赋值给`cnt`,以确保循环次数最大为`cnt`。
逐句翻译这段代码if (board_channel_number == 2) { int cnt0 = 0; for (int j = spos*4; cnt0 < cnt && j + 3 < netBuffer.size(); j += 4,cnt0++) { y[0].push_back(static_cast<double>(((netBuffer[j + 0] & 0xFF) | (netBuffer[j + 1] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution))); // //(rand()%300); y[1].push_back(static_cast<double>(((netBuffer[j + 2] & 0xFF) | (netBuffer[j + 3] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution))); //(rand()%500) } cnt = cnt0; } else if (board_channel_number == MAX_CHANNEL) { int cnt0 = 0; for (int j = spos*12;cnt0<cnt&& j + 11 < netBuffer.size(); j += 12,cnt0++) { y[0].push_back(static_cast<double>((netBuffer[j + 0] & 0xFF | (netBuffer[j + 1] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution))); // //(rand()%300); y[1].push_back(static_cast<double>((netBuffer[j + 2] & 0xFF | (netBuffer[j + 3] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution))); //(rand()%500); y[2].push_back(static_cast<double>((netBuffer[j + 4] & 0xFF | (netBuffer[j + 5] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution))); y[3].push_back(static_cast<double>((netBuffer[j + 6] & 0xFF | (netBuffer[j + 7] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution))); y[4].push_back(static_cast<double>((netBuffer[j + 8] & 0xFF | (netBuffer[j + 9] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution))); y[5].push_back(static_cast<double>((netBuffer[j + 10] & 0xFF | (netBuffer[j + 11] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution))); } cnt = cnt0; } x.resize(y[0].size()); for (size_t i = 0; i < x.size(); i++) { x[i] = i+spos; } for (size_t i = 0; i < board_channel_number; i++) { newWin->graph(i)->setData(x, y[i]); newWin->graph(i)->setPen(QPen(color[i])); } newWin->replot(QCustomPlot::rpQueuedReplot); }
如果(board_channel_number == 2)
{
int cnt0 = 0;
for (int j = spos*4; cnt0 < cnt && j + 3 < netBuffer.size(); j += 4,cnt0++)
{
y[0].push_back(static_cast<double>(((netBuffer[j + 0] & 0xFF) | (netBuffer[j + 1] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution))); // //(rand()%300);
y[1].push_back(static_cast<double>(((netBuffer[j + 2] & 0xFF) | (netBuffer[j + 3] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution))); //(rand()%500)
}
cnt = cnt0;
}
else if (board_channel_number == MAX_CHANNEL)
{
int cnt0 = 0;
for (int j = spos*12;cnt0<cnt&& j + 11 < netBuffer.size(); j += 12,cnt0++) {
y[0].push_back(static_cast<double>((netBuffer[j + 0] & 0xFF | (netBuffer[j + 1] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution))); // //(rand()%300);
y[1].push_back(static_cast<double>((netBuffer[j + 2] & 0xFF | (netBuffer[j + 3] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution))); //(rand()%500);
y[2].push_back(static_cast<double>((netBuffer[j + 4] & 0xFF | (netBuffer[j + 5] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution)));
y[3].push_back(static_cast<double>((netBuffer[j + 6] & 0xFF | (netBuffer[j + 7] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution)));
y[4].push_back(static_cast<double>((netBuffer[j + 8] & 0xFF | (netBuffer[j + 9] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution)));
y[5].push_back(static_cast<double>((netBuffer[j + 10] & 0xFF | (netBuffer[j + 11] << 8)) * board_input_range[0] * 2 / qPow(2, board_resolution)));
}
cnt = cnt0;
}
x.resize(y[0].size());
for (size_t i = 0; i < x.size(); i++)
{
x[i] = i+spos;
}
for (size_t i = 0; i < board_channel_number; i++)
{
newWin->graph(i)->setData(x, y[i]);
newWin->graph(i)->setPen(QPen(color[i]));
}
newWin->replot(QCustomPlot::rpQueuedReplot);
阅读全文