for (mwIndex i = 0; i < rows; ++i) { for (mwIndex j = 0; j < cols; ++j) { mxArray *cellElement = mxGetCell(cellArray, i + j*rows); if (cellElement && !mxIsEmpty(cellElement)) { //处理每个单元格元素,由于cell数组可以包含不同的元素. // 获取双精度浮点数 if (mxIsDouble(cellElement)) { double *data = mxGetPr(cellElement); qDebug() << data; mwSize numElements = mxGetNumberOfElements(cellElement); for (mwIndex k = 0; k < numElements; ++k) { qDebug() << "Double: " << data[k]; } } // 获取字符串 if (mxIsChar(cellElement)) { char *str = mxArrayToString(cellElement); qDebug() << "String: " << str; mxFree(str); } } } }代码含义
时间: 2024-02-10 07:20:07 浏览: 126
这段代码是用于处理 Matlab 中的 cell 数组的。首先通过遍历每个单元格元素,判断单元格是否为空,如果不为空则进一步处理。根据单元格元素的类型,分别获取其中的双精度浮点数或字符串。
如果是双精度浮点数,则通过 mxGetPr 函数获取指向数据的指针,然后遍历每个元素并输出。
如果是字符串,则通过 mxArrayToString 函数将其转换为 char* 类型,并输出。最后需要使用 mxFree 函数来释放 mxArrayToString 函数分配的内存。
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if (mxIsCell(cellArray)) { mwSize rows = mxGetM(cellArray); //行 qDebug() << rows; mwSize cols = mxGetN(cellArray); //列 qDebug() << cols; for (mwIndex i = 0; i < rows; ++i) { for (mwIndex j = 0; j < cols; ++j) { mxArray *cellElement = mxGetCell(cellArray, i + j*rows); if (cellElement && !mxIsEmpty(cellElement)) { //处理每个单元格元素,由于cell数组可以包含不同的元素. // 获取双精度浮点数 if (mxIsDouble(cellElement)) { double *data = mxGetPr(cellElement); qDebug() << data; mwSize numElements = mxGetNumberOfElements(cellElement); for (mwIndex k = 0; k < numElements; ++k) { qDebug() << "Double: " << data[k]; } } // 获取字符串 if (mxIsChar(cellElement)) { char *str = mxArrayToString(cellElement); qDebug() << "String: " << str; mxFree(str); } } } }代码含义
这段代码是用于处理 Matlab 中的 cell 数组的。首先通过 mxIsCell 函数判断输入 mxArray 是否是 cell 数组,如果是则获取其行数和列数,并通过 qDebug() 函数输出。
然后通过遍历每个单元格元素,判断单元格是否为空,如果不为空则进一步处理。根据单元格元素的类型,分别获取其中的双精度浮点数或字符串。
如果是双精度浮点数,则通过 mxGetPr 函数获取指向数据的指针,然后遍历每个元素并输出。
如果是字符串,则通过 mxArrayToString 函数将其转换为 char* 类型,并输出。最后需要使用 mxFree 函数来释放 mxArrayToString 函数分配的内存。
#include<iostream> using namespace std; class Matrix { private: int* p; int rows, cols; public: Matrix(int r, int c) { rows = r; cols = c; p = new int[rows * cols]; } Matrix(Matrix& b) { rows = b.rows; cols = b.cols; p = new int[rows * cols]; for (int i = 0; i < rows * cols; i++) { p[i] = b.p[i]; } } void input() { cout << "请输入数组值:" << endl; for (int i = 0; i < rows * cols; i++) { cin >> p[i]; } } Matrix operator+(Matrix& b) { Matrix c(rows, cols); for (int i = 0; i < rows * cols; i++) { c.p[i] = p[i] + b.p[i]; } return c; } Matrix operator=(Matrix& b) { rows = b.rows; cols = b.cols; p = new int[rows * cols]; for (int i = 0; i < rows * cols; i++) { p[i] = b.p[i]; } } void show() { cout << "数组值为:" << endl; for (int i = 0; i < rows; i++) { for (int j = 0; j < cols; j++) { cout << p[i * cols + j] << " "; } cout << endl; } } ~Matrix() { delete[]p; } }; int main() { int r, c; cout << "请输入矩阵行数和列数:" << endl; cin >> r >> c; Matrix A(r, c); cout << "请输入矩阵A的值:" << endl; A.input(); A.show(); Matrix B(A); cout << "复制构造函数测试:" << endl; B.show(); Matrix C(r, c); C = A + B; cout << "加法运算符测试:" << endl; A.show(); Matrix D(r, c); D = A; cout << "赋值运算符测试:" << endl; D.show(); return 0; }请问这段代码为什么会报错
这段代码报错的原因是在 Matrix 类中的赋值运算符重载函数中没有返回值。应该将赋值运算符重载函数的返回值类型设置为 Matrix 类型,并在函数体中添加 return *this; 语句,将当前对象的引用返回。修改后的代码如下:
```cpp
Matrix& operator=(Matrix& b) {
rows = b.rows;
cols = b.cols;
p = new int[rows * cols];
for (int i = 0; i < rows * cols; i++) {
p[i] = b.p[i];
}
return *this;
}
```
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